Answer:
Should be, (-3,5) (if rise over run aka y,x)
Step-by-step explanation:
When attempting to find a slope like this, you need to locate pretty points. Pretty points are any time the line meets an exact corner on the box. If you look at -3,1, you can see the line makes a pretty point there. Then, try to find the next one, which is at 2,-3. Once you found these pretty points, try to connect them by drawing a line towards each other THAT IS STRAIGHT until those intersect. Where they intersect is where the slope of the line is. In this case, when I drew the line, they met at <em>down three</em>, <em>over (right) 5.</em>
I think that the base of this parallelogram is 13.6 cm. I may be wrong though. Double check the work. Divide area by width and you'll get the length.
Sorry, I got a little confused with your question, but this will definitely help (I hope)
Y=mx+b
m=slope and b=y-intercept
This is just in case: y=range and x=domain(you don’t really need these though)...Best of luck to you:)
<h2><u>Direct answer</u> :</h2><h2>

</h2>
- Segment AB = Segment AD
- Segment BC = Segment DC
- Angle B and Angle D are equal.
- Segment AC bisects angle BAD
- Segment AC = Segment AC
- ∠ACD = ∠ACB
- △ABC≅△ADC under ASA congruence criterion.
- △ABC≅△ADC under SAS congruence criterion.
<h2>

</h2>
- It is given.
- It is given.
- It is given. They are also equal because the bisector AC bisects angle BAD and divides it into two equal angles which are angle B and angle D.
- It is given.
- Common side.
- Common angle.
- Two angles and one included side is equal so these two triangles are congruent under the ASA congruence criterion.
- Two sides and one included side is equal so these two triangles are congruent under the SAS congruence criterion as well.
<h3>Steps to derive these statements and reasons :</h3>
Given :
- segment AB = segment AD
- segment BC = segment DC
- ∠B =∠D
- segment AC bisects ∠BAD
This means that △ABC≅△ADC under the SAS congruence criterion because according to this criterion if two sides and one included angle is equal two triangles are congruent and since these two triangles fulfill these rules they are said to be congruent under the SAS congruence criterion. But they are also congruent under the ASA congruence criterion which states that if two angles and one included side is equal two triangles are congruent. Since △ABC and △ADC fulfill these rules too they can said to be congruent under the ASA congruence criterion.
Answer:
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Step-by-step explanation:
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