We have that
N 11)
a) graph the equation y=x²-3x-10
using a graph tool
see the attached figure
b) Determine the roots of the equations
the roots of the equations are the values for y=0
x²-3x-10=0
x²-3x-10=(x+2)*(x-5)=0
the roots are
x1=-2
x2=5
see the attached figure problem 11
N 12) what is the value of x in the equation?
3x²=7x
3x²=7x-------> 3x²-7x=0--------> x*(3x-7)=0
x1=0
3x-7=0------> 3x=7------> x=7/3
the values of x are
x1=0
x2=7/3---> 2.33
see the attached figure problem 12
N 13) what is the value of x in the equation?
x²-5x=6----------> x²-5x-6=0
x²-5x-6=0-------> (x+1)*(x-6)=0
the values of x are
x1=-1
x2=6
N 14) what is the value of x in the equation?
2x²-5x=12--------> 2x²-5x-12=0
using a graph tool
see the attached figure problem N 14
2x²-5x-12=0----------> (x+3/2)*(x-4)=0
the values of x are
x1=-3/2
x2=4
Answer:
f(x) = 2x + 7
f(15) = 2(15) + 7 = 30 + 7 = 37
Answer:
it's right
Step-by-step explanation:
3x - 5 = 7
3x = 7 + 5
3x = 12
x = 12/3
x = 4
Remember to follow PEMDAS.
First, solve the parenthesis.
(1 - 15) = -14
13 - 2(-14) ÷ 4
Next, multiply -2 and -14 (remember to bring the signs.
-2 x -14 = 28
13 + 28/4
Next, divide
28/4 = 7
13 + 7
Finally, subtract
13 + 7 = 20
20 is your answer
hope this helps