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3 years ago

Help! I need help with these problems. please help.

Mathematics

1 answer:

nata0808 [166]3 years ago

3 0

Answer:

1. medium

2. 20%

3. 12.48

4. Noah

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Anna's clothing store was open for 24 hours last weekend. If the store made $2,496 in sales over the weekend, what is the averag

Alexxx [7]

Answer:

maybe im just dumb but isnt it just 2496 divided by 24? if so the answer is 104. sorry if im wrong :/

Step-by-step explanation:

6 0

3 years ago

Sqrt(2x-6)=3-x Solve for x

soldi70 [24.7K]

Answer:

x = 3

Step-by-step explanation:

$\sqrt{2x - 6} = 3 - x$

Square both sides of the equation

$2x - 6 = (3 - x)^{2} = 9 - 6x + x^{2} \\$

$x^{2} - 8x + 15 = 0\\$

(x - 3)(x - 5) = 0

x = 3 or 5

Now, you must always check your results because a result may not satisfy the original equation.

If x = 3, then $\sqrt{2x - 6} = \sqrt{2(3) - 6} = \sqrt{6 - 6} = \sqrt{0} = 0$ and 3 - x = 3 - 3 = 0

So 3 satisfies the original.

If x = 5, then $\sqrt{2(5) - 6} = \sqrt{10 - 6} = \sqrt{4} = 2$ , but 3 - x = 3 - 5 = -2. Therefore, 5 does NOT satisfy the original equation.

That means that x = 3 is the solution to the equation.

5 0

2 years ago

Identify two values that have a value less than 3 what is the answer to this question?

Digiron [165]

Answer:

the answer is 2.9 x 10^0 and 3.2 x 10^-2

Step-by-step explanation:

10^0 is equal to 1 so 2.9 x 10^0 is really 2.9 times 1 which is less than 3

if i could get brainliest answer that would be great!

10^-2 is a exponential that makes a number go down so 3.2 going down is less than 3

8 0

3 years ago

Read 2 more answers

Do you just add it or multiply or what

Nutka1998 [239]

You need to multiply

5 0

3 years ago

Read 2 more answers

Please help

daser333 [38]

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

Statements: Reasons:

$\displaystyle 1)\, F\text{ is the midpoint of } AE$ Given

$\displaystyle 2) \, \overline{FA} \cong \overline{FE}$ Definition of Midpoint

$\displaystyle 3) \, AB\parallel DE$ Given

$\displaystyle 4)\, \angle B \cong \angle D$ Alt. Int. Angles Are Congruent

$\displaystyle 5)\, \angle A \cong E$ Alt. Int. Angles Are Congruent

$\displaystyle 6) \, \Delta BFA \cong \Delta DFE$ AAS Congruence

6 0

2 years ago