<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:32 cm2
Step-by-step explanation:Use the formula A=BH, The 7 does not count because it isn't base or height. Use 4 times 8 which will make 32 cm2.
It could be 30 to 31 but February has 28 expected from a leap year with 29 days
the answer is 134 and the Remainder is 19
