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ryzh [129]
3 years ago
7

What is the x-intercept of the line with this equation 1/3x+y=-15 Enter your answer in the box​

Mathematics
1 answer:
galina1969 [7]3 years ago
3 0

9514 1404 393

Answer:

  \boxed{-45}

Step-by-step explanation:

The x-intercept can be found by setting y=0 and solving for x.

  1/3x +0 = -15

  x = 3(-15) = 45  . . . .  multiply by 3

The x-intercept is -45.

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Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
4 years ago
Read 2 more answers
A ballroom in a hotel has the shape shown. The manager needs to determine how much carpet is needed to recarpet this area. All a
Mars2501 [29]
Area of a rectangle=length x width


You have two rectangles:


First rectangle (the biggest):
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Second rectangle (the smallest)
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width=3 yd

Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²

Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.

area of the ballroom=54 yd² +18 yd²=72 yd²
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I think hope it helps tho
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7 0
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Is this a function??
Blizzard [7]
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