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luda_lava [24]
3 years ago
8

$360 simple interest is paid when ​$6000 is borrowed for 9 months. Find the simple interest rate.

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

6 percent

Step-by-step explanation:

1 ) 360/9 = 40 - 40 dollars earned per month

2) 40 x 12 = 480 - earned per year

3) 6000/9 = 666.67 x 12 = 8000 per year

4) 480/8000 = 0.06 / 6 percent

Lets check: 6000 x 1.06 = 6360 which is the amount of interest she gets paid in 9 months

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3(x-6)^2+4 in standard form
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3x^2-36x+112

Step-by-step explanation:

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Which of these types of heath insurance can you buy through a private insurance company
larisa86 [58]

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Step-by-step explanation:

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4 0
4 years ago
Hi again could you help me please <br>Find the area of the composite shape.​
babunello [35]

Answer:

For the one on the far left its 104 m2

Step-by-step explanation:

u split the shape in a square and rectangle

them u fin the area of the square by multiplying both sides. (8*8)

then u find the area of the rectangle by using the formula

2*(16+4)

when u find both areas u count them up and it'll become 104 m squared

4 0
3 years ago
Hi plz help ASAP tyyy ^^​
Aleksandr [31]

Answer:

26.75 units²

Step-by-step explanation:

This shape can be split into 3 triangles and a square. Find the area of each shape then add them all up.

A(Square)=2(2)=4\\\\A(Triangle)=\frac{1}{2}(2)(2)=2\\\\A(Triangle)=\frac{1}{2}(5)(2)=5\\\\A(Triangle)=\frac{1}{2}(9)(3.5)=15.75\\\\A(Shape)=4+2+5+15.75=26.75

Therefore, the area of the shape is 26.75 units².

7 0
3 years ago
Please answer these with lots of detail. I want to be able to understand the topic and material well.
IRISSAK [1]

Step-by-step explanation:

Q3

(a) If 0 < |x − 1| < δ, then |f(x) − 2| < 2

What this means is, how far can x stray from the x=1 line such that f(x) stays within 2 units of the y=2 line (0 < f(x) < 4).

If we move 2 units left of x=1, we get f(x) = 4.

If we move about 3.5 units right of x=1, we get f(x) = 4.

Therefore, δ can't be more than 2.

(b) If 0 < |x| < δ, then |f(x) − 3| < 1

What this means is, how far can x stray from the x=0 line such that f(x) stays within 1 unit of the y=3 line (2 < f(x) < 4).

If we move 1 unit left of x=0, we get f(x) = 4.

If we move 1 unts right of x=0, we get f(x) = 2.

Therefore, δ can't be more than 1.

Since f(x) isn't continuous within this domain, we can't conclude that the limit exists.

Q4

(a) Yes.  If δ = 0.25, then 0.75 < x < 1.25, and f(x) > 200.

(b) No.  f(1) = 300, so even if δ = 0, f(x) will be less than 400.

(c) Yes.  If δ ≈ 0.1, then 0.9 < x < 1, and f(x) > 450.

6 0
4 years ago
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