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Lemur [1.5K]
3 years ago
11

What is the distance BC between the two horizontal parallel bars?

Mathematics
1 answer:
pochemuha3 years ago
8 0
One thing you should notice is that the transverse line and the parallel line form a right triangle. We are told that the base is 4 and the angle between the hypotenuse and the leg is 45°

From this we can solve for the second leg. Here's the list of trig functions

sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent

Since we are only given the adjacent and we are trying to solve for the opposite leg, we can deduce we use tanФ. So we get

tan45 = x/4

Multiply by 4 to isolate x and we get

4*tan45 = x
Hopes this helps!
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the area of a triangle is 124 square units. what would it's new area be if its base was half as long and its height was three ti
Montano1993 [528]
To solve this problem you must apply the proccedure shown below:

 1. You have that the formula for calculate the area of a triangle is:

 A=bh/2

 Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.

 bh/2=124
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 2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:

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 3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:

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 4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
 A'=186 units</span>²
<span>
 The answer is: </span>186 units²
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3 years ago
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jok3333 [9.3K]

Answer:

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Step-by-step explanation:

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<span>Answer: x=33/3=11


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