What is the distance BC between the two horizontal parallel bars?
1 answer:
One thing you should notice is that the transverse line and the parallel line form a right triangle. We are told that the base is 4 and the angle between the hypotenuse and the leg is 45°
From this we can solve for the second leg. Here's the list of trig functions
sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent
Since we are only given the adjacent and we are trying to solve for the opposite leg, we can deduce we use tanФ. So we get
Multiply by 4 to isolate x and we get
= x
Hopes this helps!
From this we can solve for the second leg. Here's the list of trig functions
sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent
Since we are only given the adjacent and we are trying to solve for the opposite leg, we can deduce we use tanФ. So we get
Multiply by 4 to isolate x and we get
Hopes this helps!
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<h3>I'll teach you how to solve 4m^2 - 10= -6</h3>
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Add 10 to both sides:
4m^2-10+10= -6+10
Simplify:
4m^2= 4
Divide both sides by 4:
4m^2/4= 4/4
Simplify:
m^2= 1
For x^2 = f(a) the solutions are x = -
:
m= , m= -
Simplify:
m = 1, m = -1
Your Answer Is m = 1, m = -1
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