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mihalych1998 [28]
3 years ago
11

50 POINTS

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0

Did u get help

On you question?

nexus9112 [7]3 years ago
3 0

Step-by-step explanation:

a)

\sin^{2}x + \cos^{2}x = 1

Dividing both sides by sin^2x, we get

1 +  \frac{\cos^{2}x }{ \sin^{2}x}  =  \frac{1}{\sin^{2}x }

The 2nd term on the LHS is simply cot^2x and the RHS is simply csc^2x

1 + \cot^{2}x = \csc^{2}x

b)

2 \sin  x  = 1

\sin  x  =  \frac{1}{2}

x = \sin^{ - 1} (\frac{1}{2}) =  \frac{\pi}{6}

You can also graph it to arrive at the solution.

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