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fiasKO [112]
3 years ago
6

Keyword stuffing is considered to be a black hat technique for SEO and is highly suggested today by Google.

Computers and Technology
1 answer:
klemol [59]3 years ago
3 0

Answer:

False

Explanation:

Keyword stuffing is a practice to insert an unusual large number of tag in a website to increase the page ranking in search results. This is considered an unethical Search Engine Optimization (SEO).

Google consider Keyword stuffing as unethical and it doesn't help to boost the rank of a website. More advanced algorithms are being used to filter those of the meta tags which are irrelevant or excessively out of context in a website.

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What is the difference between websites and web page​
gogolik [260]

Answer:

webpage is a single document on internet under a unique URL. Website is a collection of multiple webpages in which information on related topics or subject is linked together.

4 0
3 years ago
How many digits are in the binary number system? Explain why.
Katen [24]

Answer:

Since there are only two digits in binary, there are only two possible outcomes of each partial multiplication: If the digit in B is 0, the partial product is also 0. If the digit in B is 1, the partial product is equal to A.

Explanation:

8 0
3 years ago
Read 2 more answers
Create an application named Percentages whose main() method holds two double variables. Assign values to the variables. Pass bot
lbvjy [14]

Answer:

The codes below implement the problem statements

Explanation:

public class Percentages {

public static void computePercent (int a,int b)

{

System.out.println(a+" is "+(a*100/b)+"% of "+b);    

}

 

public static void main(String []args)

{

int a=2;

int b=5;

computePercent(a,b);

computePercent(b,a);

}

}

<u> </u>

<u>Part(b) </u>

import java.util.*;

public class Percentages {

public static void computePercent (int a,int b)

{

System.out.println(a+" is "+(a*100/b)+"% of "+b);

}

 

public static void main(String []args)

{

Scanner s= new Scanner(System.in);

int a=s.nextInt();

int b=s.nextInt();

computePercent(a,b);

computePercent(b,a);

}

}

8 0
3 years ago
What is the advantage of using a high-level language over machine language for writing computer programs?
Sveta_85 [38]

Answer:

B.  is easier to write programs

Explanation:

High-level languages are most commonly used languages these days. The ease of understanding and writing programs in high-level language has made them very popular. High-level languages are near to human. English words are used to write programs in these languages. So option B is the correct answer..

6 0
3 years ago
Read 2 more answers
Array Challenge Have the function ArrayChallenge (arr) take the array of numbers stored in arr and return the string true if any
vampirchik [111]

Answer:

The code is given as follows,

Explanation:

Code:

#include <stdio.h>

#include <string.h>  

int n; //to store size of array  

char* ArrayChallenge(int arr[]) //function returns string true or false

{

  int i, j;

  int sum = 0;

  for(i = 0; i < n; i++)

  {

      sum = sum + arr[i]; //count sum

  }  

  for(i = 0; i < n; i++)

  {

      for(j = i+1; j < n; j++) //loop for every two elements in array

      {

          if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum

          {

              printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);

              return "true"; //If proudct of two elements > 2 times sum. return true

          }

      }

  }

  return "false"; // If proudct of two elements < 2 times sum. return false

}  

int main()

{  

  printf("\nEnter size of array: ");

  scanf("%d", &n); //read size of array

  int A[n]; //array of size n

  printf("\nEnter array elements: ");

  int i;

  for(i = 0; i < n; i++)

  {

      scanf("%d", &A[i]); //read array from stdin

  }

  printf("%s\n",ArrayChallenge(A)); //ccall function and print answer

 

  return 0;

}

6 0
3 years ago
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