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3 years ago

If the relative frequencies are 0.48 and 0.52, which conclusion is most likely supported by the data?

2 answers:

8 0

I think the closest possible answer to this question is There is likely an association between the categorical variables because the relative frequencies are both close to 0.50.Thank you for your question. Please don't hesitate to ask in Brainly your

Anna007 [38]3 years ago

4 0

The right answer for the question that is being asked and shown above is that: "D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50." Given that a relative frequencies of 0.48 and 0.52, there will be an association between the categorical variables.

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The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic

pishuonlain [190]

The five-number summary and the interquartile range for the data set are given as follows:

Minimum: 24.

Lower quartile: 29.

Median: 43.

Upper quartile: 50.

Maximum: 56.

Interquartile range: 50 - 29 = 21.

<h3>What are the median and the quartiles of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

The first quartile is the median of the first half of the data-set.

The third quartile is the median of the second half of the data-set.

The interquartile range is the difference between the third quartile and the first quartile.

In this problem, we have that:

The minimum value is the smallest value, of 24.

The maximum value is the smallest value, of 56.

Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.

The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.

The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.

The interquartile range is of 50 - 29 = 21.

More can be learned about five number summaries at brainly.com/question/17110151

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3 0

2 years ago

50,000 x (2 + 5/100)<br> 50,000 x (3 + 5/100)<br> 50,000 x (4 + 5/100)<br> 50,000 x (5 + 5/100)

ELEN [110]

Answer:

Solution for What is 5 percent of 50000:

5 percent *50000 =

( 5:100)*50000 =

( 5*50000):100 =

250000:100 = 2500

Step-by-step explanation:

7 0

3 years ago

Hi! Can you help me answer this?

Free_Kalibri [48]

Answer:

$C'(x)=-\frac{148}{x^2}$

$R'(x)=-0.06$

Step-by-step explanation:

Marginal average Cost function:

$\frac{d}{dx}(\frac{148+6.3x}{x})=-\frac{148}{x^2}$

Marginal average Revenue function:

$\frac{d}{dx}(\frac{3x-0.06x}{x})=-0.06$

6 0

3 years ago

Read 2 more answers

5 (2x – 1) –7 = 2 (x – 3)

Sladkaya [172]

Answer:

x−3=x−3

Step-by-step explanation:

Evaluate (2x−1)−7, then set it equal to 2.

Subtract 7 from −1 = 2x−8

Solve 2x−8=2.

Move all terms not containing x to the right side of the equation.

Add 8 to both sides of the equation=2x=2+8

Add 2 and 8=2x=10

Divide each term by 2 and simplify.

Divide each term in 2x=10 by 2=2x/2=10/2

Cancel the common factor of 2

Cancel the common factor=10/2

Divide x by 1=x=10/2

Divide 10 by 2=x=5

Remove parentheses=x−3

List all of the solutions.

(2x−1)−7=2=x=5

x−3=x−3

7 0

3 years ago

A. [1 3

Trava [24]

<em>would be the correct answer.</em>

7 0

3 years ago

Read 2 more answers