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3 years ago

6+4/5b=9/10b solve for b

2 answers:

6 0

(6 + 4)/5b = 9/10b

Firstly multiply both sides by 5b - this will get rid of the /5b
6 + 4 = 9/5b
10 = 9/5b

Multiply for another 5b - to get rid of the remaining 5b
10*5b = 9
50b = 9
b = 9/50
b = 0.18

The answer is: b = 9/50 or 0.18

Please give me brainliest answer if I helped!

butalik [34]3 years ago

5 0

<span>This is the answer b = 60
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Is a ratio a rate always, sometimes, or never?

Shalnov [3]

A ratio is a statement of how two numbers compare so never

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3 years ago

Three merchants find a purse lying in the road. The first asserts that the discovery would make him twice as wealthy as the othe

Angelina_Jolie [31]

Answer: the system of equation would be :

A + Y = 2 (B+C)

B + Y = 3B

C + Y = 5C

the three merchants would have 10 dollars, 10 dollars, and 5 dollars respectively

Step-by-step explanation:

before finding the purse, lets assume the wealth of the 3 merchants were as follows:

first merchant = A dollars

second merchant = B dollars

third merchant = C dollars

lets assume the purse contained Y dollars

After finding the purse they all claimed they would have the following:

first merchant said adding the money in the purse to his wealth would make him twice as rich as the other two combined : A + Y = 2 (B+C)

second merchant said adding the money in the purse to his wealth would make his wealth triple : B + Y = 3B

third merchant said adding the money in the purse to his wealth would make his wealth increase five folds : C + Y = 5C

third merchant = C dollars

therefore the system of equations to represent the problems are:

A + Y = 2 (B+C)

B + Y = 3B

C + Y = 5C

2. now when the money in the purse is 20 dollars (Y= 20 dollars ), from the equations above

the second merchant will have :

B + Y = 3B

B + 20 = 3B

3B - B = 20

2B = 20

B = 10 dollars

the third merchant will have :

C + Y = 5C

C + 20 = 5C

5C - C = 20

4C = 20

C = 5 dollars

the first merchant will have :

A + Y = 2 (B+C)

A + 20 = 2 ( 10 + 5)

A = 2 (15) - 20

A = 30 - 20

A = 10 dollars

8 0

4 years ago

Find the average rate of change of g(x)=3x^2 ver the interval [-5, -3].

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Answer:

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Step-by-step explanation:

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3 years ago

Suppose that Matthew can choose to get home from work by car or bus.

Verizon [17]

Answer:

B-91%

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: arriving home after 7 p.m.

Event B: getting home by bus.

When he chooses to get home by bus, he arrives home after 7 p.m. 25 percent of the time.

This means that $P(A|B) = 0.25$

Because the bus is cheaper, he uses the bus 70 percent of the time.

This means that $P(B) = 0.7$

Probability of getting home after 7 p.m.

70% of the time he uses bus, and by bus, he arrives arrives home after 7 p.m. 25 percent of the time.

100 - 70 = 30% of the time he uses the car, and by car, he arrives home after 7 p.m. 6 percent of the time.

$P(A) = 0.7*0.25 + 0.3*0.06 = 0.193$

What is the approximate probability that Matthew chose to get home from work by bus, given that he arrived home after 7 p.m.?

$P(B|A) = \frac{0.7*0.25}{0.193} = 0.9067$

Rouding up, 91%.

So the correct answer is:

B-91%

7 0

4 years ago

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Talja [164]

To solve for the true hourly wage simply add the 2 rates together.

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The true rate would be $18.000 + $0.04 = $18.04 per hour.

7 0

3 years ago