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kompoz [17]
3 years ago
11

6+4/5b=9/10b solve for b

Mathematics
2 answers:
vovangra [49]3 years ago
6 0
(6 + 4)/5b = 9/10b

Firstly multiply both sides by 5b
- this will get rid of the /5b 
6 + 4 = 9/5b
10 = 9/5b

Multiply for another 5b - to get rid of the remaining 5b
10*5b = 9
50b = 9
b = 9/50
b = 0.18

The answer is: b = 9/50 or 0.18



Please give me brainliest answer if I helped!
butalik [34]3 years ago
5 0
<span>This is the answer b = 60
</span>
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Suzanne gets 7% commission on all of her sales. If she makes a sale of $350,000, how much commission will she make?
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Answer:

$24,500 of commission

Step-by-step explanation:

350000*0.07 = 24,500

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3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

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