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2 years ago

6+4/5b=9/10b solve for b

2 answers:

6 0

(6 + 4)/5b = 9/10b

Firstly multiply both sides by 5b - this will get rid of the /5b
6 + 4 = 9/5b
10 = 9/5b

Multiply for another 5b - to get rid of the remaining 5b
10*5b = 9
50b = 9
b = 9/50
b = 0.18

The answer is: b = 9/50 or 0.18

Please give me brainliest answer if I helped!

butalik [34]2 years ago

5 0

This is the answer b = 60

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in the number 85,549 the 5 in the hundreds place is. times that of the 5 in the thousands place.

Oksanka [162]

The value of 5 in the hundreds place is 500

The value of 5 in the thousands place is 5000

To find 500 is how many times in 5000 we will divide them

$\frac{500}{5000}=\frac{1}{10}$

Then 500 is 1/10 times that 5000

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1 year ago

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3 years ago

A coffee shop sold 7 cups,3 pints, and 9 quarts of coffee. Express the number of cups of coffee sold in base 2

sweet-ann [11.9K]

Answer:

The total number of cups of coffee sold are 51 which can be expressed in base $2$ as $110011$ .

Step-by-step explanation:

Considering the following information

$1$ cup = $1$ cup

$7$ pints = $14$ cups ∵ $1$ pint = $2$ cups
$9$ quarts = $36$ cups ∵ $1$ quart = $4$ cups

So, total number of cups will be = $51$ cups

Converting $51$ to the base $2$

Divide $51$ by $2$ by repeatedly and observe remainder

$\frac{51}{2}=25\quad \mathrm{Remainder}\quad \:1$

$\frac{25}{2}=12\quad \mathrm{Remainder}\quad \:1$

$\frac{12}{2}=6\quad \mathrm{Remainder}\quad \:0$

$\frac{6}{2}=3\quad \mathrm{Remainder}\quad \:0$

$\frac{3}{2}=1\quad \mathrm{Remainder}\quad \:1$

$\frac{1}{2}=0\quad \mathrm{Remainder}\quad \:1$

Read and observe the remainder from top to bottom would yield $110011$ .

Therefore, the total number of cups of coffee sold are 51 which can be expressed in base $2$ as $110011$ .

Keywords: base 2, number

Learn more about number bases from brainly.com/question/13725148

#learnwithBrainly

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3 years ago

Consider x^4+8xy^2=-135 find dy/dt when x=3, y=-3 and dx/dt=2

-BARSIC- [3]

Answer:

0.3224 listen in class

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3 years ago

Use the graph to complete the following. The probability that a boxer weighs between 60 and 80 pounds is %

AlexFokin [52]

Answer:

95%

Step-by-step explanation:

The Empirical rule, also the 68–95–99.7 rule, states that for a population that is approximately normal or symmetrical, nearly all of the data values will lie within three standard deviations of the mean;

68% of data values will fall within one standard deviation from the mean

95% of data values will fall within two standard deviation from the mean

99.7% of data values will fall within three standard deviation from the mean

From the graph given, we note that the weights 60 and 80 pounds fall within two standard deviations from the mean;

70 ± (2*5) = 70 ± 10 = (60, 80)

70 is the mean, 5 the standard deviation and 2 the number of standard deviations from the mean. From the Empirical rule we can conclude that the probability that a boxer weighs between 60 and 80 pounds is 95%

7 0

3 years ago

Read 2 more answers