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Vera_Pavlovna [14]
4 years ago
5

Two cars start from towns 800800 mi apart and travel toward each other. They meet after 88 hr. Find the speed of each car if one

travels 1010 mph faster than the other.
Mathematics
1 answer:
saul85 [17]4 years ago
8 0
Oh mah god this seems hard

i will try to figure it out for u 


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Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
When are two distinct lines parallel?
sergey [27]

Answer:

if the line keeps going and theynever touch

Step-by-step explanation:

8 0
3 years ago
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Calculate the value of x
Katena32 [7]

Answer:

22⁰

Step-by-step explanation:

By angle sum property :

x + 127 + 31 = 180⁰

x = 180 - 158

x = 22⁰

3 0
3 years ago
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-5y + 8 = 3y + 10. Calculate and show work
maksim [4K]
<span><span><span>2x</span>+3</span>=<span><span>[email protected]</span><span>x=6</span></span></span><span><span><span><span>(2)</span><span>(6)</span></span>+3</span>=15</span><span><span>15=</span><span>15</span></span>
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3 years ago
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PLEASE HELP!!!!!
statuscvo [17]
The second one is the function
6 0
3 years ago
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