Given:
square with sides measuring 7 cm.
3 triangles attached to three sides of the square. A line bisecting one triangle is measured at 4 cm.
Area of a square = s² = (7cm)² = 49 cm²
Area of a triangle = hb/2 = (4cm*7cm)/2 = 14 cm²
Area of the 3 triangles = 14 cm² x 3 = 42 cm²
Total area of the logo = 49 cm² + 42 cm² = 91 cm²
Answer:
The functions that represent this situation are A and C.
Step-by-step explanation:
A geometric sequence goes from one term to the next by always multiplying or dividing by the same value.
In geometric sequences, the ratio between consecutive terms is always the same. We call that ratio the common ratio.
This is the explicit formula for the geometric sequence whose first term is k and common ratio is r
Answer:
Step-by-step explanation:
6: 6, 12, 18, 24, 30, 36, 42, 48, 54
14: 14, 28, 42, 56
the LCM (least common multiple) is 42.
The roots of an equation are simply the x-intercepts of the equation.
See below for the proof that
has at least two real roots
The equation is given as: 
There are several ways to show that an equation has real roots, one of these ways is by using graphs.
See attachment for the graph of 
Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)
From the attached graph, we can see that
crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500
This means that
has at least two real roots
Read more about roots of an equation at:
brainly.com/question/12912962
Answer:
b) 3cd+3 1/3c-3d
Step-by-step explanation:
It can work well to factor the variables out so you can see the coefficients more easily:
6cd+3c-7d-3cd+4d+1/3c
= (6 -3)cd +(3 +1/3)c +(-7 +4)d
= 3cd +(3 1/3)c -3d