-2(-30)-3y =42
60-3y=42
-3y=42-60
-3y= -18
y= 6
Answer:
(10/12) / (4/6)...when dividing with fractions, flip what u r dividing by, then multiply
10/12 * 6/4 = 10/8 which reduces to 5/4 or 1 1/4
The GCF is 4x so we can write:-
4x(5x^2 + 11)
Thats your answer
Answer:
A and A
Step-by-step explanation:
Answer:
The range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].
Step-by-step explanation:
We are given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of 17 days.
Let X = <u><em>lengths of pregnancies in a small rural village</em></u>
SO, X ~ Normal(
)
Here,
= population mean = 262 days
= standard deviation = 17 days
<u>Now, the 68-95-99.7 rule states that;</u>
- 68% of the data values lies within one standard deviation points.
- 95% of the data values lies within two standard deviation points.
- 99.7% of the data values lies within three standard deviation points.
So, middle 68% of most pregnancies is represented through the range of within one standard deviation points, that is;
[
,
] = [262 - 17 , 262 + 17]
= [245 days , 279 days]
Hence, the range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].