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3 years ago

What happens to the value of the expression 2t/t as t decreases

Mathematics

1 answer:

anyanavicka [17]3 years ago

5 0

Answer:

it stays the same until t=0, where it is undefined

Step-by-step explanation:

2t/t = 2 . . . . when t ≠ 0

2t/t = undefined when t = 0.

The value of t can increase or decrease and the value of the ratio remains the same. The value has a "hole" at t=0, where it is undefined. Otherwise, its value is always 2.

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The first box plot represents the male's boxplot.

So, we have:

Upper quartile (Q3) = 14
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The IQR is the difference between the above values

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2 = 12

So: the IQR for the males' data is 12

<h3>(b) The difference in the median values</h3>

From the first and second boxplots, we have:

Median male = 10
Median female = 18

The difference (d) between these values is

d = 18 - 10

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<h3>(c) The distribution of data</h3>

This is dependent on whether the dataset has an outlier or not.

From the figure, we have:

Male's data: presence of an outlier - use median
Female's data: absence of an outlier - use mean

So: the male dataset is measured by median, while the mean is a better measure of center for the female's data

<h3>(d) Reason for outliers</h3>

A possible reason for outliers is sampling problems

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2 years ago

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What is nth for 4, 8, 16, 32?

daser333 [38]

Answer: nth=4x

Step-by-step explanation: 4,8,16,32

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3 years ago

Xin leans a 26-foot ladder against a wall so that it forms an angle of 78^{\circ} ∘ with the ground. What’s the horizontal dista

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The ladder and the wall it leans on are illustrations of right triangle

The horizontal distance from the base of the ladder is 5.41 feet

<h3>How to determine the horizontal distance?</h3>

The given parameters are:

Length (L) = 26 feet

Angle of elevation (θ) = 78 degrees

The horizontal distance (D) is calculated using the following cosine ratio

cos(θ) = D/L

Substitute known values

cos(78) = D/26

Make D the subject

D = 26 * cos(78)

Multiply

D = 5.41

Hence, the horizontal distance from the base of the ladder is 5.41 feet

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2 years ago

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2 years ago

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Question :-

DochEvi [55]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's solve ~

$\qquad \sf \dashrightarrow \: \bigg( \dfrac{1}{ \sqrt{7 + \sqrt{5} } } + \sqrt{7 + \sqrt{5} } \bigg) {}^{2}$

$\qquad \sf \dashrightarrow \: \bigg( \dfrac{1}{ \sqrt{7 + \sqrt{5} } } \bigg ) {}^{2} + \bigg( \sqrt{7 + \sqrt{5} } \bigg) {}^{2} + 2 \cdot \dfrac{1}{ \sqrt{7 + \sqrt{5} } } \cdot \sqrt{7 + \sqrt{5} }$

$\qquad \sf \dashrightarrow \: \dfrac{1}{7 + \sqrt{5} } + 7 + \sqrt{5} + 2$

$\qquad \sf \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5} }{7 + \sqrt{5} }$

$\qquad \sf \dashrightarrow \: \dfrac{68+ 16 \sqrt{5} }{7 + \sqrt{5} }$

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2 years ago