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3 years ago

How do I solve the product of 8 and 54?

Mathematics

1 answer:

Rufina [12.5K]3 years ago

7 0

Divide and u get 6 remainder 6

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PLEASE HELP!!!

PIT_PIT [208]

Answer:

Part a- after one year of depreciation the car would value $7475

part b: the car would be worth $-12650

Step-by-step explanation:

not sure if its correct but that's what I got

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3 years ago

Kayla says that the point labeled C in the diagram below is the center. Raymond says that point C is the radius. A sphere. The c

liq [111]

Answer:

Kayla is correct; the center is a fixed point in the middle of the sphere.

Step-by-step explanation:

Kayla is correct. Raymond is wrong because a point cannot be a radius: a radius is a line segment from the center to the surface.

The center is the fixed point in the middle of the sphere.

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2 years ago

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ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

3 years ago