Answer:
Runner 1 has the fastest pace
Step-by-step explanation:
The first one we need to find the slope
m = (y2-y1)/(x2-x1) = (40-0)/(4-0) =40/4 = 10 minutes per mile
The second is 8.5 minutes per mile
The third we need to find the slope
m = (y2-y1)/(x2-x1) = (90-72)/(10-8) =18/2 = 9 minutes per mile
The 1st runner has the fastest pace
For the first runner, m = (y2 - y1) / (x2 - x1)
= (40 - 0) / (4 - 0)
= 40/4
= 10
The second runner's pace is 8.5
For the third runner, m = (y2 - y1) / (x2 - x1)
= (90 - 72) / (10 - 8)
= 18/2
= 9
So the first runner has the fastest pace with 10 minutes per mile
Hope this helps, and please mark me brainliest if it does!
Oh this is easy it is 6 so yea I'm right
3(x + 7) = 57 |÷3
x + 7 = 57/3
x + 7 = 19 |-7
x = 19 - 7
x = 12
principle= 6000
time =9 years
rate = 7%
so,
compound interest = p((1+r/100)^t. -1)
= 6000((1+0.07)^9 -1)
=6000(1.84-1)
=6000*0.84
=5040
f(- 2) = - 1
To evaluate f(- 2) substitute x = - 2 into f(x) , that is
f(- 2) = 3 - (- 2)² = 3 - 4 = - 1
