Answer:
Runner 1 has the fastest pace
Step-by-step explanation:
The first one we need to find the slope
m = (y2-y1)/(x2-x1) = (40-0)/(4-0) =40/4 = 10 minutes per mile
The second is 8.5 minutes per mile
The third we need to find the slope
m = (y2-y1)/(x2-x1) = (90-72)/(10-8) =18/2 = 9 minutes per mile
The 1st runner has the fastest pace
For the first runner, m = (y2 - y1) / (x2 - x1)
= (40 - 0) / (4 - 0)
= 40/4
= 10
The second runner's pace is 8.5
For the third runner, m = (y2 - y1) / (x2 - x1)
= (90 - 72) / (10 - 8)
= 18/2
= 9
So the first runner has the fastest pace with 10 minutes per mile
Hope this helps, and please mark me brainliest if it does!
20 degrees
9 - (-11) = 20 degrees
B. y - 1 = -4[x - (-3)]
Given:
Slope = -4
Point = (-3, 1)
Required:
Point-slope form of the line
Solution:
Equation of a line in Point-slope form is given as y - b = m(x - a).
Where,
a = -3
b = 1
m = -4
Plug in the values
y - 1 = -4[x - (-3)]
