Question

Three runners are training for a marathon. One day, they all run about ten miles, each at their own constant speed. Which of the three runners has the fastest pace?

Answer 1

Answer:

Runner 1 has the fastest pace

Step-by-step explanation:

The first one we need to find the slope

m = (y2-y1)/(x2-x1) = (40-0)/(4-0) =40/4 = 10 minutes per mile

The second  is 8.5 minutes per mile

The third we need to find the slope

m = (y2-y1)/(x2-x1) = (90-72)/(10-8) =18/2 = 9 minutes per mile

Answer 2

Answer:

The 1st runner has the fastest pace

Step-by-step explanation:

For the first runner, m = (y2 - y1) / (x2 - x1)

= (40 - 0) / (4 - 0)

= 40/4

= 10

The second runner's pace is 8.5

For the third runner, m = (y2 - y1) / (x2 - x1)

= (90 - 72) / (10 - 8)

= 18/2

= 9

So the first runner has the fastest pace with 10 minutes per mile

Hope this helps, and please mark me brainliest if it does!