Three runners are training for a marathon. One day, they all run about ten miles, each at their own constant speed. Which of the
three runners has the fastest pace?
2 answers:
Answer:
Runner 1 has the fastest pace
Step-by-step explanation:
The first one we need to find the slope
m = (y2-y1)/(x2-x1) = (40-0)/(4-0) =40/4 = 10 minutes per mile
The second is 8.5 minutes per mile
The third we need to find the slope
m = (y2-y1)/(x2-x1) = (90-72)/(10-8) =18/2 = 9 minutes per mile
Answer:
The 1st runner has the fastest pace
Step-by-step explanation:
For the first runner, m = (y2 - y1) / (x2 - x1)
= (40 - 0) / (4 - 0)
= 40/4
= 10
The second runner's pace is 8.5
For the third runner, m = (y2 - y1) / (x2 - x1)
= (90 - 72) / (10 - 8)
= 18/2
= 9
So the first runner has the fastest pace with 10 minutes per mile
Hope this helps, and please mark me brainliest if it does!
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