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Citrus2011 [14]
2 years ago
5

A football team of 11 players has a mean height of 1.83m. One player is injured and is replaced by a player of height 1.85m. The

new mean height of the team is 1.84m.
What is the height of the injured player?
Mathematics
1 answer:
trapecia [35]2 years ago
7 0

Answer:

As the average has increased the height of the new player must be more then the height of the player which was injured.

The difference between the previous average and the new average is 0.01 m.

Therefore the average is increased by 0.01 m.

Therefore the total height of all the players is increased by 0.01*11=0.11 m

Therefore as the increase in the total height is made by the player with height 1.85 m,the height of the player who was injured is 1.85–0.11=1.74 m

The height of the player who was injured is 1.74 m

Step-by-step explanation:

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Answer:

<em>10,000 cups </em>

Step-by-step explanation:

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14. Find the distance between (7,217pi/180 ) and (5,-23pi/36 ) on the polar plane.
irina [24]

Answer: the distance is  3.49 units

Step-by-step explanation:

There are some ways to find the exact distance, i will calculate the distance in rectangular coordinates.

When we have a point (R, θ) in polar coordinates, we can transform it into rectangular coordinates as:

x = R*cos(θ)

y = R*sin(θ)

Then we have:

(7,217pi/180 )

R = 7

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x = 7*cos( (217/180)*pi) = -5.59

y = 7*sin( (217/180)*pi) = -4.21

So this point is (-5.59, -4.21) in rectangular coordinates.

And the other point is  (5,-23pi/36 )

R = 5

θ = -(23/36)*pi

x = 5*cos(  -(23/36)*pi ) = -2.11

y = 5*sin(  -(23/36)*pi ) = -4.53

So this point is (-2.11, - 4.53)

Then the point distance between those points is:

D = I (-2.11, -4.53) - (-5.59, -4.21) I

D = I (-2.11 + 5.59, -4.53 + 4.21) I

D = I (3.48, -0.32) I = √( (3.48)^2 + (-0.32)^2) =  3.49

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