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yuradex [85]
3 years ago
13

Solve y=f(x) for x . f(x)=23x+4 x= Question 2 Find the input when the output is 2. The input is .

Mathematics
1 answer:
Fantom [35]3 years ago
4 0

Let's find f(x) = 2, which is essentially what the problem is asking, what x corresponds to an output of 2.


Let's solve below:

f(x) = 2

  • Setting up what we know

23x + 4 = 2

  • Substituting in 23x + 4 for f(x) (I'm not sure if this is the correct expression for f(x) due to formatting issues)

23x = -2

  • Subtract 4 from both sides to make a step to isolate x (what we are trying to find)

x = - \frac{2}{23}

  • Divide both sides of the equation by 23 to isolate x

Thus the input is \boxed{x = - \frac{2}{23}}.

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F(x) = 3x, g(x) = 1/3f(x). Find g(0)
schepotkina [342]

Answer:

f(1/3)=3 try that its probably right

4 0
2 years ago
Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf
Papessa [141]

The table is missing in the question. The table is provided here :

Group 1        Group 2

 34.86            64.14      mean

 21.99            20.46      standard deviation

  7                    7                n

Solution :

a). The IV or independent variable = Group 1

    The DV or the dependent variable = Group 2

b).

  $H_0: \mu_1 = \mu_2$

  $H_a:\mu_1 < \mu_2$

  Therefore,   $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now,   $df = min(n_1 - 1, n_2 - 1)$

           df = 7 - 1

               = 6

Therefore the value of p :

  $=T.DIST(-2.579143,6,TRUE)$

 = 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

7 0
3 years ago
What is the value of the coefficient of the fourth term of the expansion of (a+b)^5 ?
melomori [17]

Answer:

I don't know if you wanted it expanded using "Pascal's Triangle" or "Binomial Theorem" but either way is the same. Your expanded equation is:

a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5

I hope this is any help to you, have a nice day.

Step-by-step explanation:

6 0
3 years ago
In 10 and 11, find the area in square units of each polygon.
alexandr1967 [171]

Answer:

10: 12 units^2 11: 33 units^2

Step-by-step explanation:

10:

Divide into square and 2 triangles (for simplicity)

square=9

one triangle=3/2

both triangles combined=3

9+3=12

11:

divide into 2 triangles

top triangle: height= 4, base=6

bottom triangle: height= 7, base=6

top=12

bottom=21

Add, 33.

7 0
2 years ago
Read 2 more answers
(Type an integer or a decimal)​
dlinn [17]

Answer:

3

Step-by-step explanation:

3y=12y-27

27=9y

y=3

3 0
3 years ago
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