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Taya2010 [7]
3 years ago
8

Please answer them! Thank you!

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0
3=2.5
4=0.1
6=9.92
7=336
8=81
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It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele
kow [346]

Answer:

t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974      

p_v =P(t_{99}>8.974)=9.43x10^{-15}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.      

Step-by-step explanation:

1) Data given and notation      

\bar X=23500 represent the sample mean  

s=3900 represent the sample standard deviation      

n=100 sample size      

\mu_o =2000 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:      

Null hypothesis:\mu \leq 2000      

Alternative hypothesis:\mu > 2000      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974      

Calculate the P-value      

First we need to calculate the degrees of freedom given by:  

df=n-1=100-1=99  

Since is a one-side upper test the p value would be:      

p_v =P(t_{99}>8.974)=9.43x10^{-15}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.      

8 0
3 years ago
On Saturday, Mark sold 2 7/8 gallons of lemonade. On the same day, Regan sold 2/3 as much lemonade as Mark. How much lemonade, i
MAXImum [283]
2 7/8= 2/3L
Divide both sides by 2/3 and get 4.31 or 4 5/16
Hope this helps!!
6 0
3 years ago
Given: XY || ZW
Gnesinka [82]

Answer:

YXV- WZV- Congruent-Vertical- AA

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through (23, -30) and (-7, 18).
babymother [125]

Answer:

slope = - \frac{8}{5}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (23, - 30) and (x₂, y₂ ) = (- 7, 18)

m = \frac{18-(-30)}{-7-23} = \frac{18+30}{-30} = \frac{48}{-30} = - \frac{8}{5}

6 0
3 years ago
Please Help!!!
DochEvi [55]

Sally earns per hour = $12

Sally works for in a week = 16 hours.

So, Sally earns in a week = 12\times16=192

Sally can save money each week= 20% of 192

\frac{20}{100}\times192=38.40

A. How much does she earn each week ? Sally earns $192 in a week.

B. How much money will she save each week? Sally will save $38.40 each week.

C. How much money will she save each month (assume there are 4.3 weeks in a month)

Savings of 1 week = $ 38.40

Savings of 4.3 weeks = 4.3\times38.40=165.12

Hence, she will save $165.12 in a month.

D. How many months will it take her to save the money?

Total money needed = $1800

Number of months needed to collect this amount =

\frac{1800}{165.12}=10.90

Hence, it will take 11 months approx to save $1800.



5 0
4 years ago
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