Answer:
Step-by-step explanation:
At a building site, an iron girder of mass 400 kg is suspended from a crane by a steel cable. Assume that the cable has a circular cross-section of diameter 24 mm.
a.What is the tensile force in newtons on the cable given that force = mass × g (where the acceleration due to gravity, g = 9.8 m s−2). Ignore the mass of the cable.(2 marks)
b.Calculate the cross-sectional area of the cable in square metres.(3 marks)
c.Show that the stress on the cable is 8.67 × 106 N m−2. Again ignore the mass of the cable.(3 marks)
d.If the Young’s modulus of the steel cable is 200 × 109 N m−2, calculate the strain in the cable.(3 marks)
e.When it is loaded with the iron girder, the steel cable stretches by 0.78 mm. Calculate what the original length of the steel cable was (i.e. its length prior to loading).(4 marks)
TOTAL: 15 marks
show working
Answer: 48x/64
Work (assuming ^ is multiplication):
12x^4/4x^16
12x ^ 4x = 48x
4 ^ 16 = 64
L= 3/4 ft
The side lengths quilt is:
Length- 4.5 ft
Breadth- 3 ft
Answer:
x>14
Step-by-step explanation:
X-3> 11
Add 3 to each side
X-3+3> 11+3
x > 14
The hole is open at 14 since it is greater than
( it would be closed if it were ≥) The line goes to the right since it is greater than
Answer:
59
Step-by-step explanation:
ur welcome
