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tester [92]
4 years ago
13

Solve the equation. |K + 9| = 4

Mathematics
1 answer:
aalyn [17]4 years ago
6 0

Answer:

A) {-13,-5}

Step-by-step explanation:

Given expression:

|K+9|=4

We need to solve for K

Since K+9 lies in the absolute brackets, so we can write the solution as (|x|\ where\ x>0\ and\ x)  :

For K+9>0

K+9=4

For K+9

K+9=-4

Solving for K individually.

Subtracting both sides by 9.

K+9-9=4-9      and K+9-9=-4-9

K=-5              and K=-13

So, the solution can be written as {-13,-5}

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Find the sum of the first 11 terms of the sequence -7,-4,-1, 2 ...
lawyer [7]

Answer:

A    The sum of the first 11 terms is 88

Step-by-step explanation:

Since -4 - (-7) = -1 - (-4) = 2 - (-1) = 3

Your sequence is an arithmetic sequence with a common difference of 3.

The formula for the sum of an arithmetic sequence is

S = \frac{n(a_{1} + a_{n}) }{2}  where a_{1} = the first term, a_{n}  =  the  last  term, n = the  number  of  terms  to  be  added, and S = the  sum

In your case a_{1}  = -7,  n = 11  and a_{n}  =  a_{11}

We know everything except the eleventh term.

So, we need to find the eleventh term or  a_{11} = a_{1} + (n - 1)d

                                                                     =  -7 + (11 - 1)3

                                                                     = -7 + 30 = 23

Now, S = \frac{11(-7 + 23)}{2}  = \frac{11(16)}{2}  = 88

The sum of the first 11 terms is 88

7 0
3 years ago
The Highly Improbable Foods Company makes vegetarian versions of burgers, hot dogs, and chicken wings, and they offer two platte
choli [55]

Answer:

  $1020

Step-by-step explanation:

Let x and y represent the numbers of Platter A and Platter B the organizer needs to purchase, respectively. The given conditions can be summarized as ...

  x + 2y ≥ 80 . . . . . . 80 or more hamburgers are required

  3x + y ≥ 95 . . . . . . 95 or more hot dogs are required

  5x +8y ≥ 380 . . . . 380 or more chicken wings are required

  16x +20y = c . . . . . c must be minimized

__

It is useful to graph these inequalities, and look for the vertex of the feasible region that is closest to the origin. That vertex is (x, y) = (20, 35). The other vertex that is close to the origin is (60, 10). The cost of that order would be $1310.

The value of an order of 20 Platter A and 35 Platter B is ...

  20×$16 +35×$20 = $320 +700 = $1020

The minimum cost of the picnic food is $1020.

8 0
3 years ago
Identify the graph of the equation. What is the angle of rotation for the equation?<br><br>xy=-2.5
Maurinko [17]

Answer:

It is B. hyperbola, 45 degrees.

SteIt is p-by-step explanation:

If we rotate the standard form  x^2 - y^2 = 1 through 45 degrees we get xy = 1/2.

xy = -2.5 comes from x^2 - y^2 = -5  being rotated 45 degrees.

3 0
4 years ago
Read 2 more answers
Help me please! If it’s right I’ll give brainliest
Wittaler [7]

Answer:

100 i think

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the reduced row echelon form of the following matrices and then give the solution to the system that is represented by the
GaryK [48]

Answer:

a)

Reduced Row Echelon:

\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right]

Solution to the system:

x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}

b)

Reduced Row Echelon:

\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right]

Solution to the system:  

x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

Step-by-step explanation:

To find the reduced row echelon form of the matrices, let's use the Gaussian-Jordan elimination process, which consists of taking the matrix and performing a series of row operations. For notation, R_i will be the transformed column, and r_i the unchanged one.

a) \left[\begin{array}{cccc}0&4&7&0\\2&1&0&0\\0&3&1&-4\end{array}\right]

Step by step operations:

1. Reorder the rows, interchange Row 1 with Row 2, then apply the next operations on the new rows:

R_1=\frac{1}{2}r_1\\R_2=\frac{1}{4}r_2

Resulting matrix:

\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&3&1&-4\end{array}\right]

2. Set the first row to 1

R_3=-3r_2+r_3

Resulting matrix:

\left[\begin{array}{cccc}1&1/2&0&0\\0&1&7/4&0\\0&0&1&-4\end{array}\right]

3. Write the system of equations:

x_1+\frac{1}{2}x_2=0\\x_2+\frac{7}{4}x_3=0\\x_3=-4

Now you have the  reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

x_3=-4\\x_2=-\frac{7}{4}x_3=7\\x_1=-\frac{1}{2}x_2=-\frac{7}{2}

b)

\left[\begin{array}{cccc}4&3&0&7\\8&6&2&-3\\4&3&2&-10\end{array}\right]

1. R_2=-2r_1+r_2\\R_3=-r_1+r_3

Resulting matrix:

\left[\begin{array}{cccc}4&3&0&7\\0&0&2&-17\\0&0&2&-17\end{array}\right]

2. Write the system of equations:

4x_1+3x_2=7\\2x_3=-17

Now you have the reduced row echelon matrix and can solve the equations, bottom to top, x_1 is column 1, x_2 column 2 and x_3 column 3:

x_3=-\frac{17}{2}\\x_1=\frac{7-3x_2}{4}

x_2 is a free variable, meaning that it has infinite possibilities and therefore the system has infinite number of solutions.

7 0
3 years ago
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