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Westkost [7]
3 years ago
12

Help me please! If it’s right I’ll give brainliest

Mathematics
2 answers:
Wittaler [7]3 years ago
4 0

Answer:

100 i think

Step-by-step explanation:

sesenic [268]3 years ago
4 0
100 i’m pretty sure.
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What is the value of log Subscript 4 Baseline 16?
Bess [88]

Answer:

The Answer is 2.

Step-by-step explanation:

5 0
4 years ago
The graph represents this piecewise function
IrinaK [193]
Top one is x+3, bottom one is 5
6 0
3 years ago
Read 2 more answers
Sum, difference, and product..help!
taurus [48]

The sum of the function will be (r – s)(x) = –2x² + x – 3, The difference of the function will be (r – s)(x) = –2x² + x – 3, and The product of the function will be (r × s)(x) = 2x³ – 6x².

The complete question is attached below.

<h3>What is Algebra?</h3>

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

The functions are given below.

r(x) = x – 3

s(x) = 2x²

The sum of the function will be

(r + s)(x) = x – 3 + 2x²

(r + s)(x) = 2x² + x – 3

The difference of the function will be

(r – s)(x) = (x – 3) – 2x²

(r – s)(x) = –2x² + x – 3

The product of the function will be

(r × s)(x) = (x – 3) (2x²)

(r × s)(x) = 2x³ – 6x²

More about the Algebra link is given below.

brainly.com/question/953809

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7 0
2 years ago
The graph models the function y = −x2 − x + 6. Which attribute(s) of the graph tell you the root(s) of the function? Determine t
Alex73 [517]
In a graph the roots of the function are given by the cut points with the x axis.
 On the other hand, we have the following equation:
 y = -x2 - x + 6
 To find the roots, we equate to zero:
 -x2 - x + 6 = 0
 Rewriting we have:
 x2 + x - 6 = 0
 (x-2) (x + 3) = 0
 The roots are:
 x1 = 2
 x2 = -3
 Answer:
 
The roots are:
 
x1 = 2
 
x2 = -3
7 0
3 years ago
Read 2 more answers
Geometry// question #8
MAVERICK [17]

Answer:

see explanation

Step-by-step explanation:

The translation rule

(x, y ) → (x + 3, y - 2 )

Means add 3 to the original x- coordinate and subtract 2 from the original y- coordinate, thus

A(- 4, 1 ) → A'(- 4 + 3, 1 - 2 ) → A'(- 1, - 1 )

B(1, 1 ) → B'(1 + 3, 1 - 2 ) → B'(4, - 1 )

C(1, - 2 ) → C'(1 + 3, - 2 - 2 ) → C'(4, - 4 )

D(- 4, - 2 ) → D'(- 4 + 3, - 2 - 2 ) → D'(- 1, - 4 )

4 0
3 years ago
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