The answer is B. Sqrt= Radical symbol 1. Subtract 5 from both sides. x^2+3-5=5-5 2. New equation. x^2-2=0 3. To make it easier I am going to add 2 to the other side and take the square root of 2. x^2-2+2=0+2, x^2=2, sqrt(x^2)= sqrt(2). 4. You will get plus or minus radical 2 because when you take the square root you will always have a positive root and a negative root of any quadratic equation. x= plus and minus sqrt(2). 5. So the answer is that it’s irrational because plus and minus radical 2 is not an integer, and secondly it isn’t a perfect root which means that plus and minus radical 2 is an irrational set roots for this quadratic equation.
