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1 year ago

Find the remainder when x³-2x²+4x-2 is divided by (x-1/2)

Mathematics

2 answers:

uranmaximum [27]1 year ago

6 0

Answer:

$\sf \bf {remainder}: -\dfrac{3}{8}$

In order to find remainder:

Follow this short technique:

Set the divisor which is x-½ to zero.

x - 1/2 = 0

x = 1/2

Then insert this following into dividend.

x³ -2x² + 4x - 2

insert x = ½

(½)³ - 2(½)² + 4(½) -2

simplify

-3/8

Gala2k [10]1 year ago

3 0

Answer:

-3/8

Step-by-step explanation:

Let's assume x - 1/2 is a zero of the polynomial :

Substitute x = 1/2 (the zero) in the equation
x³ - 2x² + 4x - 2
(1/2)³ - 2(1/2)² + 4(1/2) - 2
1/8 - 2(1/4) + 2 - 2
1/8 - 1/2
-3/8

-3/8 is the remainder.

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Find the remainder when x³-2x²+4x-2 is divided by (x-1/2)​

Find the remainder when x³-2x²+4x-2 is divided by (x-1/2)