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miskamm [114]
3 years ago
13

The cities of Portland, Oregon, and Minneapolis, Minnesota, are at about the same latitude, but Minneapolis has much hotter Summ

ers and much colder winters than Portland. Why? A) They are not at the same exact latitude. B) The ocean near Portland moderates the temperature. C) Fresh water is more likely to freeze than salt water. D) Minneapolis is much windier, due to its location in the middle of North America
Biology
1 answer:
Igoryamba3 years ago
6 0

Answer:

Option B.

It is because the ocean near Portland moderates the temperature.

Explanation:

  • The areas that are near to ocean have the moderate temperatures even in the hot seasons.
  • Portland has the pacific ocean near to it, so the ocean current regulates the temperature there. But Minneapolis lacks ocean near it, so the summer is more hotter in Minneapolis.
  • Ocean is capable of counteracting the rough distribution of radiation due to solar that reaches the Earth's surface.
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A genetically heterogeneous population of rice has a mean in the number of days to maturation of 30. Selection for decreased per
chubhunter [2.5K]

Answer:

h² = 0.6

Explanation:

Before answering the question, we need to know a few concepts.

<u>Artificial selection</u> is the selecting practice of a specific group of organisms in a population -that carry the traits of interest- to be the parents of the following generations.

Parental individuals carrying phenotypic values of interest are selected from the whole population. These parents interbreed, and a new generation is produced.

<u>The selection differential, SD,</u> is the difference between the mean value of the trait in the population (X₀) and the mean value of the parents, (Xs). So,  

SD = X₀ - Xs

<u>Heritability in the strict sense, h²</u>, is the genetic component measure to which additive genetic variance contributes. The heritability might be used to determine how the population will respond to the selection done, R.  

h² = R/SD

The <u>response to selection (R) </u>refers to the metric value gained from the cross between the selected parents. R can be calculated by multiplying the heritability h², with the selection differential, SD.  

R = h²SD  

R also equals the difference between the new generation phenotypic value (X₁) and the original population phenotypic value (X₀),  

R = X₀ - X₁

-------------------------------------------------------------------------------------------------------------

Now that we know these concepts and how to calculate them, we can solve the proposed problem.

Available data:  

  • You are selecting rice´s decreased period of maturation.
  • The population of rice has a mean maturation time of 30 days → X₀
  • Parental selected average period to maturation is 25 days → Xs
  • F1 plants mature on average in 27 days → X₁
  • N arrow sense Heritability → h²

According to what we sow previously, we need to find out the value of h².

We know that h² = R/SD, so we need to get R and SD first.  

R = X₁ - X₀

R = 27 - 30

R = -3

SD = Xs -  X₀  

SD = 25 - 30

SD = -5

Knowing this, we can calculate h²

h² = R/SD

h² = -3/-5  

h² = 0.6

 

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2 years ago
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