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SVETLANKA909090 [29]
3 years ago
11

Someone help pleeeeaSe

Mathematics
2 answers:
belka [17]3 years ago
5 0

Answer:

The answer is D. 2x/15

monitta3 years ago
3 0

Answer:

The answer is \frac{2x}{15}

First, you have to have both fractions have the same denominators. With that, you can subtract both with them.

So, the LCD (Lowest common denominator) is 15, meaning, you have to multiply both fractions to get the denominator to 15.

Multiply 4x/5 by 3 (both numerator and denominator) and multiply 2x/3 by 5 (both n and d).

After multiplying, you get 12x/15 - 10x/3

Then you subtract it and get 2x/15 !

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zhuklara [117]
Step 1: Add 3x to both sides.d−3x+3x=−9+3xd=3x−9 = ANSWER

Can you possibly help me on my recent question?
8 0
3 years ago
345+ 223<br> Use rounding or compatible numbers to estimate the sum
Mars2501 [29]
I think it is 568 if I’m not mistaken
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What is the perimeter of 6*4
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In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
3 years ago
Read 2 more answers
Which equation could be used to solve for the measure of side Q in the triangle QRS shown below given...
Rama09 [41]

The image is missing, so i have attached it

Answer:

Equation is;

q/sin 105 = 15/sin 30

Step-by-step explanation:

We are given;

Angle Q = 105°

Angle S = 30°

s = 15

From sine rule we know that;

a/sin A = b/sin B = c/sin C.

Thus, applying that to this question, we can find side q.

Thus;. q/Sin Q = s/Sin S

Plugging in the relevant values to obtain ;

q/sin 105 = 15/sin 30

8 0
3 years ago
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