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lapo4ka [179]
3 years ago
11

Seth traveled 1 mile in 57.1 second how fast did he go in miles per hour

Mathematics
2 answers:
Galina-37 [17]3 years ago
7 0
(1mile/57.1 sec) x (3,600 sec/hour) = 1 x 3600/57.1 = <em>63.05 mile/hour</em> (rounded)
Pavlova-9 [17]3 years ago
4 0

we know that

Seth traveled 1 mile in 57.1second

step 1

<u>convert 57.1 second to hour</u>

1 hour is equal to 3,600\sec

by proportion

\frac{1}{3,600}  \frac{hour}{seconds}   =\frac{x}{57.1}   \frac{hours}{seconds}\\ \\3,600*x=57.1\\\\   x=\frac{57.1}{3,600} \ hours

step 2

<u>Find the speed in miles per hour</u>

we know that

The speed is equal to

speed=\frac{distance}{time}

we have

distance= 1\  mile  \\\\   time=\frac{57.1}{3,600} \ hours

speed= \frac{1}{\frac{57.1}{3,600}}  \\\\ speed=\frac{3,600}{57.1}

speed= 63.05\frac{miles}{hour}

therefore

<u>the answer is</u>

The speed is equal to 63.05\frac{miles}{hour}


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An equation that has the highest degree of 1 is known as a linear equation. This means that no variable in a linear equation has an exponent more than 1. The graph of a linear equation always forms a straight line.

Here, Studio A rents for $75 plus $75 an hour .

Studio B rents for $150 and $50 an hour.

Let t = the number of hours and c = cost.

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Studio B: c = 150 +50·t

Part B

We solve the system of equation using substitution method, where we substitute c in the first equation with 150 +50t.

150 +50·t = 75 +75·t, subtract 75 and 50t from both sides

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c = 150 +50·3

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Part C:

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The price will be different if we rent studio A then studio B if we rent it for a different amount of time than 3 hours.

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