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Jet001 [13]
4 years ago
8

Approximately how many feet are in 5 kilometers?

Mathematics
2 answers:
yarga [219]4 years ago
8 0
1 kilometer=3280.84 feet
3280.84 *5 kilometers= is appoximetley 16404.2 feet
Sidana [21]4 years ago
5 0

Answer:

5 kilometers = 16404.2 feet

Step-by-step explanation:

Here, we need to convert the distance of 5 kilometers into feet. The relation between feet and kilometers is as follows :

1 kilometers = 3280.84 feet

Now using unitary method kilometers can be converted to feet.

5 kilometers = 3280.84 × 5 feet

⇒ 5 kilometers = 16404.2 feet

So, there are 16404.2 feet in 5 kilometers. Hence, this is the required solution.

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Answer:

The number of the class containing the  largest score can be found in frequency  24 and the class is  98 - 103

For the third class 78 - 83 ; the upper limit = 83

The class width for this histogram 5

The number of students that took the exam simply refers to the frequency is  84

The percentage of students that scored higher than 95.5 is 53%

Step-by-step explanation:

The objective of this question is to use the following histogram that shows the exam scores for a Pre-algebra class to answer the question given:

NOW;

The table given in the question can be illustrated as follows:

S/N           Class                Score          Frequency

1                 68  - 73            70.5           0

2                73 - 78             75.5           4

3                78 - 83             80.5           8

4                83 - 88             85.5           12

5                88 - 93            90.5           16

6                93 - 98            95.5           20

<u>7                98 - 103           100.5          24                            </u>

TOTAL:                                                 84

<u>                                                                                             </u>

<u />

a) The number of the class containing the  largest score can be found in frequency  24 and the class is  98 - 103

b) For the third class 78 - 83 ; the upper limit = 83  ( since the upper limit is derived by addition of  5 to the last number showing  in the highest value specified by the number in the class interval which is 78 ( i.e 78 + 5 = 83))

c)   The class width for this histogram 5 ; since it  is the difference  between the upper and lower boundaries  limit of the given class.

So , from above the difference in any of the class will definitely result into 5

d) The number of students that took the exam simply refers to the frequency ; which is (0+4+8+12+16+20+24) = 84

e) Lastly; the percentage of students that scored higher than 95.5 is ;

⇒\dfrac{20+24}{84} *100

= 0.5238095 × 100

= 52.83

To the nearest percentage ;the percentage of students that scored higher than 95.5 is 53%

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Step-by-step explanation:

You can save yourself some trouble if you realize that one of the angles in one pair must match one of the angles in the other pair.

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If f(x) = x² + 7, what is the value of f(4)? Enter the answer in the box. PLEASE HELP .
bazaltina [42]

Answer:

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Step-by-step explanation:

With f(4), we plug 4 into the function.

f(4) = 4² + 7

f(4) = 16 + 7

f(4) = 23

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