90/139 is the only fraction not equivalent to 45/70.
To find if a fractions are equivalent, divide the numerator by the denominator for each fraction.
45/70=0.642857
27/42=0.642857
9/14=0.642857
63/98=0.642857
Notice how all of these get you the same number. However, when you divide 90 by 137, you get 0.64748, which is not the same as the others. Therefore, 90/137 is the fraction that is not equivalent to 45/70.
Using the Factor Theorem, it is found that yes, it is possible for a sixth degree polynomial function with integer coefficients to have no real zeroes, as they can have three complex-conjugate pairs.
<h3>What is the Factor Theorem?</h3>
The Factor Theorem states that a polynomial function with roots
is given by:
![f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%28x%20-%20x_1%29%28x%20-%20x_2%29%20%5Ccdots%20%28x%20-%20x_n%29)
In which a is the leading coefficient.
If a complex number is a root of a function, it's conjugate will also be a root. Thus, with three pairs of complex-conjugate roots, for example,
, a sixth degree function with no real zeros is formed, so the answer is Yes.
More can be learned about the Factor Theorem at brainly.com/question/24380382
Answer:
7a²/16
Step-by-step explanation:
Area of the triangle PTS
½ × a × a
a²/2
Length of PS:
sqrt(a² + a²)
asqrt(2)
Length of MS:
¼asqrt(2)
Triangles MCS and TPS are similar
With sides in the ratio:
¼asqrt(2) : a
sqrt(2)/4 : 1
Area of triangle SMC:
A/(a²/2) = [(sqrt(2)/4)]²
2A/a² = 1/8
A = a²/16
Area of PTMC
= a²/2 - a²/16
= 7a²/16
Answer:
rad66/11
Step-by-step explanation:
Using Sohcahtoa, you can find that the tangent is the opposite side over the adjacent side. This means that the tangent of angle X is 2rad6/2rad11. You then simplify it to rad6/rad11. Preferably, a radical shouldn't be in the denominator. You can muliply both sides by rad 11 to balance the equation into rad66/11.
Answer:
Por lo tanto será 45 minutos
Step-by-step explanation: