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tester [92]
3 years ago
7

Which vectors represent the reflection of the vector <3, -7> across the x-axis? A. [3/7} B. [-3/7] C. <-3, 7> D. &lt

;3, 7> E. [7/-3] F. <7, -3>
Mathematics
2 answers:
Alexandra [31]3 years ago
3 0

Answer:

D)    < 3, 7)>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given that the vector < 3 , -7 >

Given the vector reflection across the x-axis

                   (x,y) → (x , -y)

The vector < 3,-7> →< 3, -(-7)>

                  < 3,-7> →< 3, 7)>

Scorpion4ik [409]3 years ago
3 0

Answer:

The Answer is A and B.  I got it correct.

Step-by-step explanation:

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Micah is flying a kite and has used all of the 50 meters of the string. If the kite is 13 meters above the ground, what is the a
Norma-Jean [14]

Answer:

60.0735651 degrees

Step-by-step explanation:

So the hypotenuse is 50 and the vertical leg is 13

For the angle, you need to find the sine (opposite and hypotenuse)

sin(x) = 13/50

x = asin(13/50)

x = 60.0735651

4 0
3 years ago
Find the product : (3x-1)•(2x^2+5x-4)
Karolina [17]

Answer:

27x

Step-by-step explanation: hope this helps

6 0
2 years ago
Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are
Svetlanka [38]

Answer:

(a) Number of sets B given that

  • A⊆B⊆C: 2¹⁰.  (That is: A is a subset of B, B is a subset of C. B might be equal to C)
  • A⊂B⊂C: 2¹⁰ - 2.  (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

<h3>(a)</h3>

Let x_1, x_2, \cdots, x_{20} denote the 20 elements of set X.

Let x_1, x_2, \cdots, x_{10} denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain x_1, x_2, \cdots, x_{10}.

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from x_1, x_2, \cdots, x_{20}.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves 2^{10} -2 = 1024 - 2 = 1022 possibilities.

<h3>(b)</h3>

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's 2^{20} = 1048576 possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only 2^{20} - 2^{10} possibilities left.

5 0
3 years ago
WORTH 100 POINTS WHOEVER ANWSERS FIRST I WILL REWARD BRAINLIEST HELP PLEASE What are five one step equations with the answer of
Harlamova29_29 [7]

Answer and Explanation:

Five one-step equations with the answer of 0:

1. x - 8 = -8

2. x - 4 = -4

3. x / 2 = 0

4. x - 3 = -3

5. 5 * x = 0

Five one-step equations with the answer of -5:

1. y + 2 = -3

2. y - 3 = -8

3. y + 10 = 5

4. y * (-2) = 10

5. y / 1 = -5

Five one-step equations with the answer of 4:

1. 4 * z = 16

2. 8 - z = 4

3. 7 + z = 11

4. z / 2 = 2

5. z + 11 = 7

Hope these help!

5 0
3 years ago
Read 2 more answers
Y = x-2<br> What is the y-intercept of this line?
serg [7]

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

3 0
3 years ago
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