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tester [92]
3 years ago
7

Which vectors represent the reflection of the vector <3, -7> across the x-axis? A. [3/7} B. [-3/7] C. <-3, 7> D. &lt

;3, 7> E. [7/-3] F. <7, -3>
Mathematics
2 answers:
Alexandra [31]3 years ago
3 0

Answer:

D)    < 3, 7)>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given that the vector < 3 , -7 >

Given the vector reflection across the x-axis

                   (x,y) → (x , -y)

The vector < 3,-7> →< 3, -(-7)>

                  < 3,-7> →< 3, 7)>

Scorpion4ik [409]3 years ago
3 0

Answer:

The Answer is A and B.  I got it correct.

Step-by-step explanation:

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a

Step-by-step explanation:

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3 years ago
Which two values of x are roots
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The answer is C. 

To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients. 

a = 4 (number attached to x^2)
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c = 1 (number with no variable attached)

Now we can put this into the quadratic equation. 

\frac{-b +/-  \sqrt{ b^{2} -4ac} }{2a}

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4 years ago
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8 0
3 years ago
Find the error in the following sample of work, if one exists.
ch4aika [34]

Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

<u>Line 1:</u>

In line 1, the equation is given and is completely fine.

y^{2}+8xy+2y+16x=0

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

<u>Line 2:</u>

In line 2, the terms are grouped, from which we can factor out common terms.

(y^{2}+8xy)+(2y+16x)=0

This is also fine.

<u>Line 3:</u>

In line 3, the common term y is taken out from group 1 and 2 from other group.

y(y+8x)+2(y+8x)=0

which is exactly what is given in line 3.

<u>Line 4:</u>

In line 4 the common factors can be seen and easily split into 2 factors.

(y+2)(y+8x)=0

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

3 0
3 years ago
Suppose that the weight of an newborn fawn is Uniformly distributed between 2.5 and 4 kg. Suppose that a newborn fawn is randoml
Lubov Fominskaja [6]

Answer:

a) The mean is 3.25

b) The standard deviation is 0.433

c) The probability that fawn will weigh exactly 3.7 kg is 0

d) The probability that a newborn fawn will be weigh between 2.9 and 3.5 is 0.4

e) The probability that a newborn fawn will be weigh more than 3.3 is 0.4667

f) The probability that a newborn fawn will be weigh more than P(x > 2.9 | x < 3.7) is 0.6667

g) The 59th percentile is 3.385

Step-by-step explanation:

a) In order to calculate the mean we would have to make the following calculation:

mean = (4 + 2.5) / 2 = 3.25

b) In order to calculate the standard deviation we would have to make the following calculation:

standard deviation = (4 - 2.5) / √(12) = 0.433

c) P(X = 3.7) = 0

d)  In order to calculate the probability that a newborn fawn will be weigh between 2.9 and 3.5 we would have to make the following calculation:

P(2.9 < X < 3.5) = (3.5 - 2.9) / (4 - 2.5) = 0.4

e) In order to calculate the probability that a newborn fawn will be weigh more than 3.3 we would have to make the following calculation:

P(X > 3.3) = (4 - 3.3) / (4 - 2.5) = 0.4667

f) P(X > 2.9 | X < 3.7) = P(X > 2.9 and X < 3.7) / P(X < 3.7) = P(2.9 < X < 3.7) / P(X < 3.7) = [(3.7 - 2.9) / (4 - 2.5)] / [(3.7 - 2.5) / (4 - 2.5)] = 0.6667

g)  In order to calculate the 59th percentile we would have to make the following calculation:

P(X < x) = 0.59

(x - 2.5) / (4 - 2.5) = 0.59

x = 3.385

6 0
4 years ago
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