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zubka84 [21]
4 years ago
9

CAN SOMEONE PLEASE ANSWER!

Mathematics
2 answers:
Agata [3.3K]4 years ago
5 0

Answer:

100x^8

Step-by-step explanation:

\sqrt{10,000x^6^4}

The square root of 10,000 = 100

The square root of x^64 = x^8

So \sqrt{10,000x^6^4} = 100x^8

Andrew [12]4 years ago
3 0

Hey there!!

Things to remember:

  • √ = something raised to the power 1/2

Given:

... √(10000x⁶⁴)

We can write this as:

... (√10000)×(√x⁶⁴)

The root of 10000 is 100

... 100×(x⁶⁴)¹/²

... 100 × x^64/2

... 100 × x^32

Hence, the answer is :

... <em>100x³² </em>

<em>Hope my answer helps!</em>



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2/3(18x - 12) = 7 – 3(x –3)​
julsineya [31]

Answer:

x=8/5

Step-by-step explanation:

2/3(18x-12)=7-3(x-3)

2/3(18x-12)=7-3x+9

12x-8=-3x+16

12x-(-3x)-8=16

12x+3x-8=16

15x-8=16

15x=16+8

15x=24

x=24/15

simplify

x=8/5

7 0
4 years ago
Each glass vase at a Mother’s Day brunch has 8 stems, of which 37.5% are stems of greenery. How many stems of greenery are in ea
ella [17]
I believe the answer is there are 3 stems of greenery in each vase.

You just do 8 times 37.5% or 0.375 and get 3.
6 0
3 years ago
What is the name of a three dimensional shape that has four triangular faces and one rectangular face?
Mama L [17]
Hey there!

The shape you're looking for is a rectangular pyramid. A rectangular pyramid has a rectangular base and four triangles that make up the four sides and meet up at the points at the very top. I've attached a picture so you can see it for yourself. 

Hope this helped you out! :-)

7 0
3 years ago
6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

8 0
3 years ago
Evaluate the expression.<br><br> 2^3=___
victus00 [196]
2^3=2*2*2=4*2=8
the answer is 8
7 0
3 years ago
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