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Crank
3 years ago
14

I have a problem -3x-7=-13. When isolating x I divide x by -3 then divide -13 by -3 correct?

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0

Hello!

no, that is not the correct way to isolate x. you were somewhat on the right track however.

here's the correct way:

add 7 to both sides to get -3x = -6

then divide both sides by -3 to get x = 2

I hope this helps, and have a nice day!

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Step-by-step explanation:

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On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

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XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
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Find the volume of the composite solid. Round your answer to the nearest hundredth.
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Step-by-step explanation:

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2 years ago
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Answer:

Please check the explanation.

Step-by-step explanation:

From the given diagram, we can observe that r and s are the two parallel lines intersected by the two transversal lines.

Therefore, the pairs of alternating interior angles formed by the two transversal lines are:

  • ∠1  & ∠5
  • ∠2 & ∠4
  • ∠2 & ∠7
  • ∠3 & ∠6

We know that alternating interior angles formed by a transversal line are congruent.

Thus,

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  • ∠2 = ∠4
  • ∠2 = ∠7
  • ∠3 = ∠6

Part a)

Given

m∠1 = 3x + 42

m∠5 = 8x - 8

As

∠1  = ∠5

So

3x + 42 =  8x - 8

flipe the equation

8x - 8 = 3x + 42

subtract 3x from both sides

8x - 8 - 3x = 3x + 42 - 3x

5x - 8 = 42

add 8 to both sides

5x - 8 + 8 = 42 + 8

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divide both sides by 5

5x/5 = 50/5

x = 10.0000 (Rounded to four decimal places)

Thus, the value of x = 10.0000 (Rounded to four decimal places)

Part b)

Given

m∠6 = 12°

It is clear that angles ∠6 and angle ∠7 lie on a straight line.

Thus,

The sum of ∠6 and ∠7 is 180°.

∠6 + ∠7 = 180°

substituting m ∠ 6 = 12° in ∠6 + ∠7 = 180°

12° + ∠7 = 180°

subtract 12 from both sides

12° + ∠7 - 12° = 180° - 12°

∠7 = 168°

Thus, measure of angle ∠7 = 168°.

We already know that alternating interior angles formed by a transversal line are congruent.

∠7 and ∠2 are alternating interior angles.

Thus,

∠2 = ∠7

As ∠7 = 168°.

Therefore,

∠2 =  168°

Hence, we conclude that

∠2 =  168°

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