The equation of the line in slope-intercept form is y = -2/3x - 11
<h3>Equation of a line </h3>
The line is the distance between two points. The equation in slope-intercept form is y = mx + b
Given the equation in point-slope form y+7 = -2/3(x+6)
Write in slope intercept form
3(y+7) = -2(x+6)
3y + 21 = -2x - 12
3y = -2x - 33
y = -2/3x - 11
Hence the equation of the line in slope-intercept form is y = -2/3x - 11
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3 / 5 = (x+1) / (y-2)
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↓ multiply by 5 / 3
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1 = 5 * (x+1) / 3 * (y-2)
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↓ move and simplify
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5x + 5 = 3y - 6
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↓ minus 5
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5x = 3y - 11
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↓ divide by 5
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Answer : x = (3y - 11) / 5