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vladimir1956 [14]
4 years ago
11

!!!!!!Need help with #’s 1 through 4 please !!!!!!!

Mathematics
1 answer:
Ivenika [448]4 years ago
3 0
1. is 5 dollars an hour
2.it represents the amount of money he gets in an hour
Sorry i could not help with 3 and 4 



WE HAVE STEM BRAINS
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Which type of graph would be best to use for representing the strength category of hurricanes that develop in the Atlantic Ocean
muminat

Line graph line plot

5 0
3 years ago
A metalworker has a metal alloy that is 30​% copper and another alloy that is 55​% copper. How many kilograms of each alloy shou
Ilya [14]
<h3>Answer:</h3>
  • 32 kg of 30% copper
  • 48 kg of 55% copper
<h3>Step-by-step explanation:</h3>

Let x represent the mass of 55% copper alloy that is to be used in the mix. Then 80-x is the mass of 30% copper alloy to be used. The total amount of copper in the mix is then ...

... 0.55x + 0.30(80-x) = 0.45·80

... 0.25x = 12 . . . . . . simplify, subtract 24

... x = 48 . . . . . . . . . divide by the coefficient of x

... 80-x = 32 . . . . . . the mass of 30% copper alloy required

The metalworker should combine 32 kg of 30% copper alloy with 48 kg of 55% copper alloy to make 80 kg of 45% copper alloy.

4 0
3 years ago
Mr. Richard owns an orchard that has a rectagular fence . The orchard is 36 yards long and 18 yards wide . if he walks across th
Sergio [31]

Answer:

40.2 Yards

Step-by-step explanation:

To find the diagonal length of the orchard, we need to use the Pythagorean Theorem. The formula of the Pythagorean Theorem is:

c²= a² + b²

a = 36 Yards

b = 18 Yards

Now let's plug in our values to the formula.

c² = a² + b²

c² = 36² + 18²

c² = 1296 + 324

c² = 1620

Now to find the value of c we need to get the square root of both sides.

\sqrt{c^{2}}=\sqrt{1620}

c = 40.2

So the diagonal length of Mr. Richard's orchard is 40.2 Yards.

7 0
4 years ago
What is the perimeter of this title ?
Kryger [21]

Answer:

24 in

Step-by-step explanation:

Perimeter is adding the length of all the sides together. So, 10 + 6 + 8 = 24

7 0
3 years ago
How many numbers between 1 and 2005 are integer multiples of 3 or 4 but not 12?
siniylev [52]

Count the number of multiples of 3, 4, and 12 in the range 1-2005:

⌊2005/3⌋ ≈ ⌊668.333⌋ = 668

⌊2005/4⌋ = ⌊501.25⌋ = 501

⌊2005/12⌋ ≈ ⌊167.083⌋ = 167

(⌊<em>x</em>⌋ means the "floor" of <em>x</em>, i.e. the largest integer smaller than <em>x</em>, so ⌊<em>a</em>/<em>b</em>⌋ is what you get when you divide <em>a</em> by <em>b</em> and ignore the remainder)

Then using the inclusion/exclusion principle, there are

668 + 501 - 2•167 = 835

numbers that are multiples of 3 or 4 but not 12. We subtract the number multiples of 12 twice because the sets of multiples of 3 and 4 both contain multiples of 12. Subtracting once removes the multiples of 3 <em>and</em> 4 that occur twice. Subtracting again removes them altogether.

7 0
3 years ago
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