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2 years ago

8

You are planning to purchase ten pencils of type A which cost a total of $14.00 and five pencils of type B which cost $15.00. A)

what is the price unit of each type per pencils? B) which is a better buy?

1 answer:

muminat2 years ago

8 0

Answer:

A.1 type A pencil costs $1.40. 1 type B pencil costs $3.00.

B. Type A pencils are a better buy.

Step-by-step explanation:

A.14.0 divided by 10 is 1.4. 15.0 divided by 5 is 3.

B. 10 type b pencils cost $30.00. 10 type a pencils cost less, only $14.00, so it is a better buy. Hope this helped!

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What would the answer be

Hoochie [10]

Answer:

B.

Step-by-step explanation:

process of elimination. the red dot is not a 1/4 of the number of lines, so it cant be 12.25, 13.625 is impossible because it has a value less than 13, and 12.625 is impossible as well because it has a value less than 12.5 therefore 12.375 is the best answer, and the only correct answer

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3 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

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3 years ago

Read 2 more answers

If f(x) =4x-2 and g(x) =2x+8, what is h (x) when h (x) =f (x) +g(x)

melisa1 [442]

Answer:

h(x)=4x_2+2x+8

h(x)=6x+6

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2 years ago

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Help with number 14 please :))

Degger [83]

Answer:

b = - 5

Step-by-step explanation:

(k + a )(k + x) + 1 = k^2 + kx + ak + ax + 1

I think the way to solve this is to worry about the 36

k^s + 1 + ak should equal 36

We know that a = 2

k^2 + 1 + 2k = 36

k^2 + 2k + 1 - 36 = 0

k^2 + 2k - 35 = 0

(k + 7)(k - 5) = 0

k = -7 is the only acceptable answer. It is given that K < 0.

bx = kx + ax

b = k + a

b = - 7 + 2

b = - 5

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Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

DiKsa [7]

Answer:

12

Hope it helps

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