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11111nata11111 [884]
3 years ago
14

(X-2)2/4+(y+5)2/9=1 what is the length of major axis of this equation?

Mathematics
1 answer:
makvit [3.9K]3 years ago
7 0
Step 1: Add (-1)/9 to both sides.<span><span><span><span><span><span>12</span>x</span>+<span><span>29</span>y</span></span>+<span>19</span></span>+<span><span>−1</span>9</span></span>=<span>1+<span><span>−1</span>9</span></span></span><span><span><span><span>12</span>x</span>+<span><span>29</span>y</span></span>=<span>89</span></span>Step 2: Add (-2)/9y to both sides.<span><span><span><span><span>12</span>x</span>+<span><span>29</span>y</span></span>+<span><span><span>−2</span>9</span>y</span></span>=<span><span>89</span>+<span><span><span>−2</span>9</span>y</span></span></span><span><span><span>12</span>x</span>=<span><span><span><span>−2</span>9</span>y</span>+<span>89</span></span></span>Step 3: Divide both sides by 1/2.<span><span><span><span>12</span>x</span><span>12</span></span>=<span><span><span><span><span>−2</span>9</span>y</span>+<span>89</span></span><span>12</span></span></span><span>x=<span><span><span><span>−4</span>9</span>y</span>+<span>169</span></span></span>Answer:<span>x=<span><span><span><span>−4</span>9</span>y</span>+<span>16<span>9</span></span></span></span>
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If you have 14 feet of fencing, what are the areas of the different rectangles you could enclose with the fencing? Consider only
disa [49]

Answer:

Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²

Step-by-step explanation:

Feets of fencing = 14

Perimeter = 14

Let x = Length y = width

Perimeter = 2(x + y)

For x = 1

2(1 + y) = 14

1 + y = 7

y =6

Area of rectangle ; x *y = 1 * 6 = 6 ft²

For x = 2

2(2 + y) = 14

2 + y = 7

y = 5

Area of rectangle ; x *y = 2 * 5 = 10 ft²

For x = 3

2(3 + y) = 14

3 + y = 7

y =4

Area of rectangle ; x *y = 3 * 4 = 12 ft²

For x = 4

2(1 + y) = 14

4 + y = 7

y = 3

Area of rectangle ; x *y = 4 * 3 =12 ft²

Hence, Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²

8 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

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3 years ago
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hichkok12 [17]

Answer:

14

Step-by-step explanation:

we are solving 15 + |-3| - 4

anything inside |   | means it's absolute value.

absolute value means that even if it is a negative number inside, it will change to positive. if it is a positive number inside, it will stay the same.

so |-3| is 3.

15 + 3 - 4

18 - 4 = 14.

we got the answer

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