(3√2+4)(√2−1)=_____+√2<br> help lol

A cylinder’s volume can be calculated by the formula V=pir^2h , where V stands for volume, R for the base radius and H for the c

sasho [114]

Answer:

Step-by-step explanation:

Formula

V pi * r^2 * h

Givens

r = 3 m

h = 6 m

pi = 3.14 when used.

Solution

V = pi r^2 * h

V = pi * 3^2 * 6

V = 9 * 6 * pi

V = 54 * pi Volume in terms of pi

V = 54*3.14 Volume using a value for pi

V = 169.56 to the hundred's place.

3 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

4 years ago

Please help again. i dont know how to solve this one either.

Oksana_A [137]

3 x 3 x 17 x oweueueueuee

4 0

2 years ago

Read 2 more answers

You are choosing between two long-distance fun plans plan a has a monthly fee of $15 with a charge of 0.09 Per minute of long di

dusya [7]

Answer:

Step-by-step explanation:

This is a system of inequalities problem. We first need to determine the expression for each phone plan.

Plan A charges $15 whether you use any minutes of long distance or not; if you use long distance you're paying $.09 per minute. The expression for that plan is

.09x + 15

Plan B charges $12 whether you use any minutes of long distance or not; if you use long distance you're paying $.15 per minute. The expression for that plan is

.15x + 12

We are asked to determine how many minutes of long distance calls in a month, x, that make plan A the better deal (meaning costs less). If we want plan A to cost less than plan B, the inequality looks like this:

.09x + 15 < .15x + 12 and "solve" for x:

3 < .06x so

50 < x or x > 50

For plan A to be the better plan, you need to talk at least 50 minutes long distance per month. Any number of minutes less than 50 makes plan B the cheaper one.

8 0

3 years ago

when multiplie discount are used if an item is first discount by 40%,then again by 30%.then again by 10%,the final or cumulative

nadezda [96]

The answer is : 40+30=70
70+10=80 therfore the final or cumulative discount is 80%

4 0

3 years ago

(3√2+4)(√2−1)=_____+√2 help lol