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lesya [120]
3 years ago
11

the formula p = nc - e , gives the profit p when a number of items n are each sold at a cost c and expenses e are subtracted. If

p=4050, n=3000, and e=300, what is the value of c?
Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0

Answer:

  c = 1.45

Step-by-step explanation:

Solving the equation for c, we find ...

  p +e = nc

  c = (p +e)/n

Filling in the values given, we have ...

  c = (4050 +300)/3000 = 4350/3000 = 1.45

The value of c is 1.45.

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Suppose that in a random sample of size 200, standard deviation of the sampling distribution of the sample mean 0.08. researcher
sertanlavr [38]

Answer:

400

Step-by-step explanation:

The computation of the sample size needed is shown below:

Since at the sample size of 200 there is a standard deviation of 0.08

But when the standard deviation is 0.04 so the sample size is 400

As sample standard deviation would be inversely proportional to the square root of the sample size

7 0
3 years ago
If u answer ill give brainlist
makkiz [27]

Answer:

120; 643 units squared

Step-by-step explanation:

Perimeter: Add all the sides, so 120 units

_________________________________

Area: First multiply 19 by 24 for the first shape within this other shape, so That equals 456 units squared. Since we know that one whole side is 36 we can subtract 19 from it to get the lower side of the smaller shape and then multiply that by 11. So the smaller side ends up being 17. So 17 times 11 equals: 187 units squared. Then just add the areas together 187+456=643 units squared.

3 0
2 years ago
The amount of a radioactive isotope decays in half every year the amount of the isotope can be modeled by f(x)=3461/2x and f(1)=
pychu [463]

Answer:

1 represents the number of years passed.

step -by-step explanation:

The amount of a radioactive isotope decays in half every year. The amount of the isotope can be modeled by f(x) = 346 (1/2)x and f(1) = 173

Here 1 represents the number of years that passed.

So 1 represents the number of years.

Hope this will helpful.

Thank you.

4 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
Someone please help, i don't understand
Mars2501 [29]
Y=-2x+0 haahahaha hope i helped i think
4 0
3 years ago
Read 2 more answers
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