Question

In Exercises 7 and 8, identify the segment bisector of JK. Then find JM.

Answer 1

#7) M is the Midpoint of JK. Since there is no segment through M, then there is no segment bisector.

JM = 7x + 5, MK = 8x (Given)

JM ≡ MK (definition of midpoint)

JM = MK (definition of congruency)

7x + 5 = 8x (substitution)

5 = x (subtraction property of equality)

JM = 7x + 5 → JM = 7(5) + 5 → JM = 35 + 5 → JM = 40

#8) M is the Midpoint of JK. the line passing through M is line l, so line l is the segment bisector.

JM = 3x + 15, MK = 8x + 25 (Given)

JM ≡ MK (definition of midpoint)

JM = MK (definition of congruency)

3x + 15 = 8x + 25 (substitution)

15 = 5x + 25 (subtraction property of equality - subtracted 3x)

-10 = 5x (subtraction property of equality - subtracted 25)

-2 = x (division property of equality)

JM = 3x + 15 → JM = 3(-2) + 15 → JM = -6 + 15 → JM = 9

Answer 2

Answer:

JM=9

Step-by-step explanation:

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