All categories

3 years ago

In Exercises 7 and 8, identify the segment bisector of JK. Then find JM.

Mathematics

2 answers:

Mademuasel [1]3 years ago

7 0

#7) M is the Midpoint of JK. Since there is no segment through M, then there is no segment bisector.

JM = 7x + 5, MK = 8x (Given)

JM ≡ MK (definition of midpoint)

JM = MK (definition of congruency)

7x + 5 = 8x (substitution)

5 = x (subtraction property of equality)

JM = 7x + 5 → JM = 7(5) + 5 → JM = 35 + 5 → JM = 40

#8) M is the Midpoint of JK. the line passing through M is line l, so line l is the segment bisector.

JM = 3x + 15, MK = 8x + 25 (Given)

JM ≡ MK (definition of midpoint)

JM = MK (definition of congruency)

3x + 15 = 8x + 25 (substitution)

15 = 5x + 25 (subtraction property of equality - subtracted 3x)

-10 = 5x (subtraction property of equality - subtracted 25)

-2 = x (division property of equality)

JM = 3x + 15 → JM = 3(-2) + 15 → JM = -6 + 15 → JM = 9

Travka [436]3 years ago

7 0

Answer:

JM=9

Step-by-step explanation:

she explained it

You might be interested in

Pleas answer it now in two minutes

soldier1979 [14.2K]

Answer:

the length measure of OP is 35 yd

Step-by-step explanation:

The problem says that the two shapes are congruent. This means they have the same length and angle measurements. So, in order to find out what OP is, you have to find its corresponding part which is WX. The measurement of WX is 35 yd which means that the measurement of OP is also 35 yd because they are corresponding side lengths therefore being the same.

6 0

3 years ago

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind. Find the speed of the wind

Lunna [17]

Given:

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind.

Pilot's speed in still air is 315 miles per hour.

To find:

The speed of the wind.

Solution:

Let the speed of wind be x miles per hour.

Speed with wind = 315+x miles per hour

Speed against wind = 315-x miles per hour

We know that,

$Time=\dfrac{Distance}{Speed}$

According to the question,

$\dfrac{450}{315+x}=\dfrac{360}{315-x}$

Divide both sides by 90.

$\dfrac{5}{315+x}=\dfrac{4}{315-x}$

By cross multiplication, we get

$5(315-x)=4(315+x)$

$5(315)-5x=4(315)+4x$

$5(315)-4(315)=4x+5x$

$(5-4)315=9x$

Divide both sides by 9.

$\dfrac{(1)315}{9}=x$

$35=x$

Therefore, the speed of wind is 35 miles per hour.

4 0

3 years ago

A. 4 b. 5 c. 9 d. 25

trapecia [35]

5t=45
45/5=9

The answer is C
Hope I helped

7 0

3 years ago

What are the next three terms in the sequence3,6,9,12,...?

Vinil7 [7]

Answer:

15, 18, 21

Step-by-step explanation:

3, 6, 9, 12, 15, 18, 21...

3 x 5 = 15

3 x 6 = 18

3 x 7 = 21

Hope this helps! :)

8 0

3 years ago

Question 6

ad-work [718]

Answer:

The input for the method is a continuous function f, an interval [a, b], and the function values f(a) and f(b). The function values are of opposite sign (there is at least one zero crossing within the interval). Each iteration performs these steps: Calculate c, the midpoint of the interval, c = a + b2.

Step-by-step explanation:

trust

7 0

2 years ago