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3 years ago

In Exercises 7 and 8, identify the segment bisector of JK. Then find JM.

Mathematics

2 answers:

Mademuasel [1]3 years ago

7 0

#7) M is the Midpoint of JK. Since there is no segment through M, then there is no segment bisector.

JM = 7x + 5, MK = 8x (Given)

JM ≡ MK (definition of midpoint)

JM = MK (definition of congruency)

7x + 5 = 8x (substitution)

5 = x (subtraction property of equality)

JM = 7x + 5 → JM = 7(5) + 5 → JM = 35 + 5 → JM = 40

#8) M is the Midpoint of JK. the line passing through M is line l, so line l is the segment bisector.

JM = 3x + 15, MK = 8x + 25 (Given)

JM ≡ MK (definition of midpoint)

JM = MK (definition of congruency)

3x + 15 = 8x + 25 (substitution)

15 = 5x + 25 (subtraction property of equality - subtracted 3x)

-10 = 5x (subtraction property of equality - subtracted 25)

-2 = x (division property of equality)

JM = 3x + 15 → JM = 3(-2) + 15 → JM = -6 + 15 → JM = 9

Travka [436]3 years ago

7 0

Answer:

JM=9

Step-by-step explanation:

she explained it

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This linear programming problem can be formulated as two inequalities (in addition to the usual constraints that the variables be non-negative). One of these expresses the constraint on weight. Let f and c represent numbers of food and clothing containers, respectively.

40f +25c ≤ 21000

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We can subtract the boundary line equation of the first inequality from that of 5 times the second to find f:

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c = 1400 -4f = 466 2/3

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(f, c) = (233, 467)

The other vertices of the feasible region are associated with one or the other variable being zero: (f, c) = (0, 840) or (350, 0).

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Trying these in the constraint inequalities gives ...

40·233 +25·467 = 20,995 < 21000
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The answer to the question will be the feasible region vertex that maximizes the number of people helped. That is, we want to maximize ...

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