3 years ago

PLEASE HELP ME PLEASE HELP ASAP PLEASE HELP PLEASE AND THANK YOU

Mathematics

1 answer:

Allushta [10]3 years ago

7 0

Answer:

y =mx + c

7 = 5/2 (-2) + c

7 = - 5 + c

c = 7 + 5

c = 12

Therefore, y = 5/2x + 12

Multiply through by 2

2y = 5x + 24

You're welcome

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Solve for x: 6x + 1 over 4 (4x + 8) > 12

sukhopar [10]

Answer:

A. $x>\frac{10}{7}$ .

Step-by-step explanation:

We have been given an inequality $6x+\frac{1}{4}(4x+8)>12$ . We are asked to solve the given inequality for x.

Using distributive property, we will get:

$6x+\frac{1}{4}*4x+\frac{1}{4}*8>12$

$6x+x+2>12$

$7x+2>12$

Subtract 2 from both sides:

$7x+2-2>12-2$

$7x>10$

Divide both sides by 7:

$\frac{7x}{7}>\frac{10}{7}$

$x>\frac{10}{7}$

Therefore, option A is the correct choice.

3 0

3 years ago

An extremely large sink hole has opened up in a field just outside of the city limits. It is difficult to measure across the sin

abruzzese [7]

Triangle ABC and triangle DCE are congruent, so line DE = line AB

Use the cosine rule to find angle ACB
$52.2^{2}= 50^{2}+ 70^{2}-(2*50*70*cos(ACB))$
$2724.84=7400-(7000cos(ACB))$
$2724.84-7400=-7000cos(ACB)$
$-4675.16=-7000cos(ACB)$
$\frac{4675.16}{7000}=cos(ACB)$
$Angle ACB= cos^{-1} ( \frac{4675.16}{7000})$
Angle ACB = 48.1°