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Lemur [1.5K]
3 years ago
11

Jessica thinks that she might have made a mistake on her tax return and paid more tax than she needed to. Complete the statement

s describing what Jessica can do.
Jessica can hire
to check her tax return. If a mistake is found, Jessica can file Form
to have the IRS correct the mistake and refund any excess taxes she paid.
Mathematics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

A certified accountant and can file 1040X

Step-by-step explanation:

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Answer:

15 in.

Step-by-step explanation:

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A random variable is uniformly distributed over the interval [-4, 6]. find the mean, variance, and standard deviation of .
Lyrx [107]

The mean, variance, and standard deviation are 1, 8,33 and 2.89

<h3>How to find the mean, variance, and standard deviation?</h3>

The distribution is given as:

[a, b] = [-4, 6]

The mean is calculated as;

Mean = (a + b)/2

So, we have

Mean = (-4 + 6)/2

Evaluate

Mean = 1

The variance is calculated as;

Var = (b - a)^2/12

So, we have

Var = (6 + 4)^2/12

Evaluate

Var  = 8.33

The standard deviation is calculated as;

SD= sqrt(Var)

So, we have

SD = sqrt(8.33)

Evaluate

SD = 2.89

Hence, the mean, variance, and standard deviation are 1, 8,33 and 2.89

Read more about uniform distribution at:

brainly.com/question/16238191

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8 0
2 years ago
PLZZZ HELP Find the inverse of a 2x2 matrix<br><br><br> Plz give answer .
liraira [26]

Answer:

\left[\begin{array}{cc}-\frac{1}{2}&\frac{1}{6}\\-\frac{1}{2}&\frac{1}{3}\\\end{array}\right]

Step-by-step explanation:

If a 2x2 matrix is given as:

\left[\begin{array}{cc}a&b\\c&d\\\end{array}\right]

The inverse is:

\frac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\\\end{array}\right]

Our matrix given is:

\left[\begin{array}{cc}-4&2\\-6&6\\\end{array}\right]

<em />

<em>Using the formula, let's find the inverse:</em>

<em>\frac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\\\end{array}\right]\\=\frac{1}{(-4)(6)-(-6)(2)}\left[\begin{array}{cc}6&-2\\6&-4\\\end{array}\right]\\=\frac{1}{-12}\left[\begin{array}{cc}6&-2\\6&-4\\\end{array}\right]\\=\left[\begin{array}{cc}-\frac{1}{2}&\frac{1}{6}\\-\frac{1}{2}&\frac{1}{3}\\\end{array}\right]</em>

4 0
3 years ago
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