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ozzi
3 years ago
7

HELP PLEASE PLEASE HELP Solve for t. -10t − -17t − 10t + -13 = 11

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

-10t - (-17t) - 10t + (-13) = 11   (two negative signs makes a positive)

-10t + 17t - 10t - 13 = 11  Combine like terms

-3t - 13 = 11    Add 13 on both sides

-3t = 24     Divide -3 on both sides

t = -8




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4(4/5) + √(4/5) + 0.2 - 5(4/5)

= 16/5 + (2√5/5) + (1/5) - 4

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6 0
3 years ago
A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

7 0
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Answer:

Step-by-step explanation:

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blue line is parallel to y-axis

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Answer:

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Rewrite equation

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Subtract 4 from both sides

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