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Aleks [24]
2 years ago
11

The temperature of a cup of coffee t minutes after it has been poured is described by the function

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
5 0
A) You want to find t such that
.. C(t) = d
.. d = 20 +60*0.95^t
.. (d -20)/60 = 0.95^t
.. log((d -20)/60) = t*log(0.95)
.. t = log((d -20)/60)/log(0.95) . . . . . . time to cool to d degrees (d > 20)

b) C'(t) = 60*0.95^t*ln(0.95)
.. C'(1) = 60*0.95*ln(0.95) ≈ -2.924 °C/min
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By listing the samples in descending order we have - Sample B, Sample E, Sample A, Sample C, and Sample D.

Step-by-step explanation:

Step 1; First, we must convert all the temperatures into a common scale. The given temperatures are in three different units i.e. °C, K, and °F. Here we convert all the units into K.

To convert °C to K, we add 273.15 with the °C , 44 °C= 44 + 273.15 =     317.15 K.

To convert °F, we have the formula (112°F − 32) × (\frac{5}{9}) + 273.15, so

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112 °F = (112 - 32) × (\frac{5}{9}) + 273.15 = 317.594 K.

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Sample C = 316.483 K,

Sample D = 310 K,

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