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3 years ago

Please help on this triangle

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer:

h ≈ 13.4

Step-by-step explanation:

Since the triangle is right we can use the sine ratio to find h

sin48° = $\frac{opposite}{hypotenuse}$ = $\frac{h}{18}$

Multiply both sides by 18

18 × sin48° = h

⇒ h = 13.4 cm ( to 1 dec. place )

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A worker is handling the four of a rectangle room that is 12 feet by 15 feet.The tiles are square with side lengths 1 1/3 feet.

Anon25 [30]

Answer:

Step-by-step explanation:

The measure of the floor of the rectangular room that is 12 feet by 15 feet. The formula for determining the area of a rectangle is expressed as

Area = length × width

Area of the rectangular room would be

12 × 15 = 180 feet²

The tiles are square with side lengths 1 1/3 feet. Converting 1 1/3 feet to improper fraction, it becomes 4/3 feet

Area if each tile is

4/3 × 4/3 = 16/9 ft²

The number of tiles needed to cover the entire floor is

180/(16/9) = 180 × 9/16

= 101.25

102 tiles would be needed because the tiles must be whole numbers.

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3 years ago

Write each proof as a two column proof

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

What can be used as a statement in a two column proof?

A two-column proof consists of a list of statements, and the reasons why those statements are true. The statements are in the left column and the reasons are in the right column. The statements consists of steps toward solving the problem.

8 0

3 years ago

Find soluton to x^2-14x+49=25

Artyom0805 [142]

$\boxed{x=12 \ and \ x=2}$

<h2>Explanation:</h2>

In this exercise, we have the following equation:

$x^2-14x+49=25$

We can write this Quadratic Equation in Standard Form as follows:

$x^2-14x+49=25 \\ \\ Subtract \ 25 \ from \ both \ sides: \\ \\ x^2-14x+49-25=25-25 \\ \\ x^2-14x+24=0 \\ \\$

So this is a Non-perfect Square Trinomial. To factor out this, let's choose two numbers such that:

The sum is -14
The product is 24

Those numbers are:

-12 and -2
SUM: -12-2 = -14
PRODUCT: (-12)(-2)=24

So we can write this as:

$x^2 + (a + b)x + ab=(x + a)(x + b) \\ \\ a=-12 \\ b=-2 \\ \\ x^2-14x+24=(x-12)(x-2)=0 \\ \\ So \ the \ solutions \ are: \\ \\ \boxed{x=12 \ and \ x=2}$