Question

Please help asap need it done. What is the measure of ∠CED and ∠ACD?

Answer 1

Answer:

$m\angle CED= 64\°$  

$m\angle ACD=124\°$  

Step-by-step explanation:

In the figure given:

∠ABC = 93°

∠BAC = 31°

∠CDE = 60°

To find ∠CED and ∠ACD.

Solution:

In triangle ABC, we are given two vertex angles. We can find the third angle as angle sum of triangle = 180°.

∠ABC = 93° , ∠BAC = 31°

∠BCA=  $180\°-(93\°+31\°)$

∠BCA = 56°

$m\angle BCA+m\angle ACD=180\°$    [Supplementary angles forming a linear pair]

$m\angle ACD=180\°-56\°$

$m\angle ACD=124\°$   (Answer)

In triangle CDE:

$m\angle CDE+m\angle CED = m\angle ACD$   [Exterior angle theorem :Exterior angle of a triangle is equal to sum of opposite interior angles ]

$60\°+m\angle CED = 124\°$

$m\angle CED= 124\°-60\°$

$m\angle CED= 64\°$      (Answer)

Answer 2

Answer:

m\angle CED= 64\°  

m\angle ACD=124\°  

Step-by-step explanation:

get an A!