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SIZIF [17.4K]
3 years ago
8

Quinn returned home one summer's day to find it sweat-inducingly hot! He turned the air conditioner on and fell asleep. The room

's temperature decreased by 0.5 ∘ Celsius each minute, and Quinn woke up 60 minutes later when it was 10 ∘ Celsius.
Mathematics
2 answers:
wel3 years ago
7 0
Cooling was bringing the temperature down 1 degree c every 2 minutes. 60min /2 =30°c . 10°c +30°c =40°c
The temperature was 40°c when he first returned home.
eimsori [14]3 years ago
7 0

Answer: Temperature after 60 minutes is -20° C.

Step-by-step explanation:

Since we have given that

Temperature at initial = 10° C

Decrement rate = 0.5°C per minute

Number of minutes taken = 60 minutes

According to question,

Temperature after 60 minutes would be

10+60\times -0.5\\\\=10^\circ C-30^\circ C\\\\=-20^\circ C

Hence, Temperature after 60 minutes is -20° C.

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At a farmer’s market, a basket of strawberries costs $20 and a basket of peaches costs $18. On Saturday, $430 worth of strawberr
stellarik [79]
I hope this helps you

3 0
3 years ago
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What is the greatest common factor of the polynomial below? 8x^2-4<br>   A.4x B.2x C.4x^2 D.2x^2
Vadim26 [7]

none of those are right it is 4 because there is no x behind the 4.

5 0
3 years ago
. A family spends 1/10 of its annual income for housing, 1/4 for food and clothing, 1/5 for general expenses, and 2/15 for enter
IrinaVladis [17]
First you have to set the fractions with an equal denominator
hint: numerator/denominator
all of the denominators go into sixty

1/10=6/60
1/4=15/60
1/5=12/60
2/15=8/60

then you will have to add the numerators
(6+15+12+8)/60 = 41/60
simplify if possible but it's not necessary for this one
8 0
3 years ago
John enlarged one side of his square flower bed by 8 ft to make it into a rectangle. The area of the new flower bed is 3 times t
Mila [183]

If the side of the square flower bed was enlarged by 8 feet and the area of the new flower bed was 3 times the area of the old one then the length of the side of the old flower bed was 4 feet.

Given that the side of square flower bed was enlarged by 8 feet and the area of the new flower bed was 4 feet.

We are required to find the length of the side of the old flower bed.

We know that the area of rectangle is equal to the product of length and breadth of that rectangle.

let x represents the side of the square old flower bed.

Dimensions of new rectangular flower bed:

Width=x

Length =x+8

Area=3*x^{2}

=3x^{2}

Thus:

x(x+8)=3x^{2}

x^{2}+8x=3x^{2}

2x^{2}=8x

2x=8

x=4

Hence if the side of the square flower bed was enlarged by 8 feet and the area of the new flower bed was 3 times the area of the old one then the length of the side of the old flower bed was 4 feet.

Question is incomplete as the next part of the question is as under:

Calculate the length of the side of the old flower bed?

Learn more about area at brainly.com/question/25292087

#SPJ4

7 0
2 years ago
Please help !!!!!!!!!!!
Mkey [24]

Answer:

insert the day in for D

so only one solution matches all 4 results:D

23(1) +11 = 34

23(2) + 11 = 57

23(3) + 11 = 80

23(4) + 11 = 103

6 0
3 years ago
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