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SIZIF [17.4K]
3 years ago
8

Quinn returned home one summer's day to find it sweat-inducingly hot! He turned the air conditioner on and fell asleep. The room

's temperature decreased by 0.5 ∘ Celsius each minute, and Quinn woke up 60 minutes later when it was 10 ∘ Celsius.
Mathematics
2 answers:
wel3 years ago
7 0
Cooling was bringing the temperature down 1 degree c every 2 minutes. 60min /2 =30°c . 10°c +30°c =40°c
The temperature was 40°c when he first returned home.
eimsori [14]3 years ago
7 0

Answer: Temperature after 60 minutes is -20° C.

Step-by-step explanation:

Since we have given that

Temperature at initial = 10° C

Decrement rate = 0.5°C per minute

Number of minutes taken = 60 minutes

According to question,

Temperature after 60 minutes would be

10+60\times -0.5\\\\=10^\circ C-30^\circ C\\\\=-20^\circ C

Hence, Temperature after 60 minutes is -20° C.

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Rasida ran 5 more miles than 2 times the number of miles Diallo ran this week. Rasida ran 27 miles this week.
Sholpan [36]

Answer:

11

Step-by-step explanation:

Rasida ran 27 miles total.  she ran 5 more miles than double what Diallo ran.

27-5=22

Now divide 22 by 2 to get how many miles Diallo ran.

7 0
3 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

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3 years ago
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If you don30,000 + 3,500 you get 33,500 so the answer is 33,500☺️
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