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3 years ago

Is 2x-4=2x-7 infinite no solution or one solution

Mathematics

1 answer:

Elan Coil [88]3 years ago

8 0

Answer:

no solution

Step-by-step explanation:

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Solve the following equation : 6x =12

densk [106]

X=2 here very simple

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3 years ago

Solve the equation 6x + 3y = 15 for y. What does y equal if x = 2? If x = 5?

horsena [70]

6(2)+3y=15
12+3y=15
-12 -12
3y=3
3y/3 3/3
y=1

6(5)+3y=15
30+3y=15
-30 -30
3y=-15
3y/3 -15/3
y= -5

4 0

2 years ago

Read 2 more answers

PLEASE HELP: Find the measure of the angle indicated. Arc BC is 80 degrees.

Marina CMI [18]

The angle is 80 degrees. The measure of an angle is the exact same as the angle measure of the included arc, so that makes angle BAC 80 degrees

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3 years ago

4x+5y=-5 and what is it graphed

viva [34]

Answer:

go to m a t h w a y . c o m but dont add the spaces and it will give you the answer just type it exactly how you did on here

Step-by-step explanation:

3 0

3 years ago

Solve the following equation:

Rama09 [41]

Complete the square.

$z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0$

$\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4$

Use de Moivre's theorem to compute the square roots of the right side.

$w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)$

$\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2$

Now, taking square roots on both sides, we have

$z^2 + \dfrac12 = \pm w^{1/2}$

$z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2$

Use de Moivre's theorem again to take square roots on both sides.

$w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)$

$\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}$

$w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)$

$\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}$

3 0

1 year ago