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2 years ago

Find the missing height in the diagram. 4 ft 81 12 ft feet 3 64 16 ft

Mathematics

2 answers:

Serggg [28]2 years ago

7 0

Answer:

2feet at the least man

ozzi2 years ago

6 0

Answer:

4ft

Step-by-step explanation:

i did 12ft - 8ft which would of gotten the length of the bottom length.

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How do you factor 6x^2+x+2

Svetradugi [14.3K]

Answer:

$6x^{2} +x + 2$ cannot be factored

Step-by-step explanation:

The equation cannot be simplified so you have to use the quadratic formula

and you will get imaginary numbers from the formula

7 0

3 years ago

What is 8 over 9 as a decimal please explain:D

Yanka [14]

0.88888889
just devide 8 by 9

5 0

3 years ago

Find the area of the kite !!!! PLEASE HELP!!!!

Andrew [12]

ANSWER

D. 18 m^2

EXPLANATION

The area of a kite is half the product of the diagonals.

The diagonals of the kite are

3+3=6m

and

2+4=6m

The area of the kite

$= \frac{1}{2} \times 6 \times 6$

$= 3 \times 6$

$= 18 {m}^{2}$

The correct answer is D.

7 0

3 years ago

Factor completely. ay^2 + 2ay - 3a

coldgirl [10]

Ay^2+2ay-3a
a(y^2+2y-3)
a(y-1)(y+3)

8 0

3 years ago

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago