We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
Answer:
3x^2y
Step-by-step explanation:
hope this helps : )
Answer:
75.062c
Step-by-step explanation:
To find the missing side use pythagorean theorem
So 
Solve for b, b= 6.021
To find the area use 
bh
So (6.021+19)(6)= area
And you get 75.062
Answer:
5x-13= 12
Step-by-step explanation:
5x-13 = 12
+13 +13
------------------------
5x= 25
x=5
Answer:
the answer to your question is (9,3)
