I am thinking of a number that is at most 13.

A 32 year old mother realized that her age is twice the sum of her two children ages. Her son Jose is two years older than her d

jenyasd209 [6]

Again, guess and test should work perfectly fine. Since 2(x+y)=32, x+y = 16. Because y-2 =x, y could be = 9 and x = 7. Hope that help!

3 0

3 years ago

Read 2 more answers

Yeah I need help…..<br> Do your work soldiers

Aloiza [94]

I can’t, sir! I cannot leave my post to help with your math problems, over!

8 0

2 years ago

Read 2 more answers

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

b

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago

Sophie borrowed $2000 and took 3 years to repay the loan and $900 interest.

dedylja [7]

I = p * r * n

i is the interest
p is the principal
r is the interest rate per time period
n is the number of time periods.

in your problem:

i = 900
p = 2000
r = what you want to find
n = 3 years

formula becomes 900 = 2000 * r * 3

solve for r to get r = 900 / 2000 / 3 = .15

that's .15 interest rate per year = 15% per year.

at a nominal interest rate of .15 per year, the interest rate per month would be .15/12 = .0125 per month.

the remaining balance at the end of 6 month is equal to 1907.140183

7 0

3 years ago

Find the 12th term in the following arithmetic sequence

sattari [20]

It is going up by 5 so i believe your answer would be 57

4 0

2 years ago